LG+C60+F+G and LG+C20+F+G.
My question is :If I do LG+C60+F+G with a guide tree, will it be faster than a LG+C60+F+G ? Is it a way to use PMSF ?
I think there is something I don't understand well in this Table from your GitHub and
Wang paper :In this Table
| Models | CPU time | Wall-clock time | RAM usage |
|---|---|---|---|
LG+F+G |
43h:38m:23s | 3h:37m:23s | 1.8 GB |
LG+C20+F+G |
584h:25m:29s | 46h:39m:06s | 38.8 GB |
LG+C60+F+G |
1502h:25m:31s | 125h:15m:29s | 112.8 GB |
LG+PMSF+G |
73h:30m:37s | 5h:7m:27s | 2.2 GB |
What PMSF refer to ? Do I need to replace PMSF by a model (for ex. C60 or C20 ?) ? Are they use a Cxx instead with a guide tree ? Because I don't understand what model they use to save all this time in the paper.
I have 500 fasta of 121 species and 35 000 positions. I tried with the following line command :
for f in *-modified.fasta; do echo "iqtree-mpi -s $f -m LG+C60+F+G -ft replica-1-concat.fasta-modified.treefile -nt 8 -mem 60G"; done > all-jobs.cmds
I succeeded in getting 15 trees (2 days of calculation, and it seems much compared to your data set of Brown who have results in 5h with 68 sequences, 43615 amino-acid sites, 16 CPU... and I use 32 CPU).
Plus, for the 75 others, I had this erreur (not for the 15 first fasta, I don't understand) :
ERROR: STACK TRACE FOR DEBUGGING:
ERROR: 1 double* aligned_alloc<double>(unsigned long)
ERROR: 2 PhyloTree::initializeAllPartialLh(int&, int&, PhyloNode*, PhyloNode*)
ERROR: 3 PhyloTree::initializeAllPartialLh()
ERROR: 4 computeSiteFrequencyModel(Params&, Alignment*)
ERROR: 5 runPhyloAnalysis(Params&, Checkpoint*)
ERROR: 6 main()
ERROR: 7 __libc_start_main()
ERROR: Not enough memory, allocation of 59743927072 bytes failed (bad_alloc)
Do you think my parameters -nt 8 -mem 60G are good ?
According to you, using PMFS, what would be the most pertinent ? What we want is the equivalent of a C60, without having as much computing time.
Best regards
Richard GOUY
On 13 Apr 2020, at 2:37 pm, Richard Benji <rgo...@gmail.com> wrote:HelloI have a question about the use of PMSF. In the paper of Wang 2018 and on the GitHub page (https://github.com/Cibiv/IQ-TREE/wiki/Complex-Models), you demonstrate that PMSF is (to do simple) as efficient as Cxx or CAT+GTR, but faster.You show that with LG+PMSF+Γ allows us to be faster for thanLG+C60+F+G andLG+C20+F+G.My question is :If I doLG+C60+F+G with a guide tree, will it be faster than aLG+C60+F+G ? Is it a way to use PMSF ?
I think there is something I don't understand well in this Table from your GitHub andWang paper :In this Table
Models CPU time Wall-clock time RAM usage LG+F+G43h:38m:23s 3h:37m:23s 1.8 GB LG+C20+F+G584h:25m:29s 46h:39m:06s 38.8 GB LG+C60+F+G1502h:25m:31s 125h:15m:29s 112.8 GB LG+PMSF+G73h:30m:37s 5h:7m:27s 2.2 GB What PMSF refer to ?
Do I need to replace PMSF by a model (for ex. C60 or C20 ?) ? Are they use a Cxx instead with a guide tree ? Because I don't understand what model they use to save all this time in the paper.
I have 500 fasta of 121 species and 35 000 positions. I tried with the following line command :for f in *-modified.fasta; do echo "iqtree-mpi -s $f -m LG+C60+F+G -ft replica-1-concat.fasta-modified.treefile -nt 8 -mem 60G"; done > all-jobs.cmdsI succeeded in getting 15 trees (2 days of calculation, and it seems much compared to your data set of Brown who have results in 5h with68 sequences, 43615 amino-acid sites, 16 CPU... and I use 32 CPU).Plus, for the 75 others, I had this erreur (not for the 15 first fasta, I don't understand) :ERROR: STACK TRACE FOR DEBUGGING:
ERROR: 1 double* aligned_alloc<double>(unsigned long)
ERROR: 2 PhyloTree::initializeAllPartialLh(int&, int&, PhyloNode*, PhyloNode*)
ERROR: 3 PhyloTree::initializeAllPartialLh()
ERROR: 4 computeSiteFrequencyModel(Params&, Alignment*)
ERROR: 5 runPhyloAnalysis(Params&, Checkpoint*)
ERROR: 6 main()
ERROR: 7 __libc_start_main()
ERROR: Not enough memory, allocation of 59743927072 bytes failed (bad_alloc)Do you think my parameters-nt 8 -mem 60G are good ?
According to you, using PMFS, what would be the most pertinent ? What we want is the equivalent of a C60, without having as much computing time.
Best regardsRichard GOUY--
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