In the case of a car whose rest length is greater than the length of the garage, from pov of the garage, the car will fit inside if its speed is sufficient fast due to length contraction of the car. But from the pov of the moving car, the length of garage will contract, as close to zero as one desires as its velocity approaches c, so the car will NOT fit inside the garage. Someone posted a link to an article which claimed, without proof, that this apparent contradiction can be resolved by the fact that simultaneity is frame dependent. I don't see how disagreements of simultaneity between frames solves this apparent paradox. AG
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On 12/4/2024 8:43 PM, Alan Grayson wrote:
On Wednesday, December 4, 2024 at 2:41:25 PM UTC-7 Jesse Mazer wrote:
On Wed, Dec 4, 2024 at 4:06 PM Alan Grayson <agrays...@gmail.com> wrote:
In the case of a car whose rest length is greater than the length of the garage, from pov of the garage, the car will fit inside if its speed is sufficient fast due to length contraction of the car. But from the pov of the moving car, the length of garage will contract, as close to zero as one desires as its velocity approaches c, so the car will NOT fit inside the garage. Someone posted a link to an article which claimed, without proof, that this apparent contradiction can be resolved by the fact that simultaneity is frame dependent. I don't see how disagreements of simultaneity between frames solves this apparent paradox. AG
Can you think of any way to define the meaning of the phrase "fit inside" other than by saying that the back end of the car is at a position inside the garage past the entrance "at the same time" as the front end of the car is at a position inside the garage but hasn't hit the back wall? (or hasn't passed through the back opening of the garage, if we imagine the garage as something like a covered bridge that's open on both ends) This way of defining it obviously depends on simultaneity, so different frames can disagree about whether there is any moment where such an event on the worldline of the back of the car is simultaneous with such an event on the worldline of the front of the car.
Jesse
Let's suppose that in the frame of the car, the front and back of the car are simultaneously inside the garage at some speed v. How does this account for the fact that the length of the garage schrinks arbitarily close to zero as v approaches c, which ostensibly leads to, or tends to the opposite conclusion? AGThink about what that mean operationally. You have a photon detector at the middle of the car and mirrors at each end of the car positioned to send photons from lights at each end of the garage. When the detector receives a photon from each direction at the same time that means the ends of your care are simultaneously at the ends of the garage IN THE CARS REFERENCE FRAME. Now think about what it means in the garage reference frame.
Brent
>But the conclusion that it fits seems to contradict the fact that the length of the garage shrinks from the car's pov
>> from the garage man's POV the garage's length does not shrink but the car's length does. In Special Relativity time is diluted by the factor γ which is equal to 1 / √(1 - v²/c²) ; and an object's length will be reduced by a factor of the inverse of γ. So Length contraction reduces the length by 1/γ, and Time Dilation increases the time interval by γ. For example, at 87% the speed of light length contracts to half its original rest length, and time dilutes by a factor of two.The bottom line is that when two observers are in relative motion, like the garage man and the car driver are, they measure space and time differently. An event has a position and a time, and the closing of both garage doors is an event, so they will not agree if that event happened simultaneously when the entire car was in the garage or not.
> I don't think your proposed solution works. We're assuming the rest frame length of the car is larger than the rest frame length of the garage.
> IOW, unless we can establish that there's an objective reality where both observers see the same thing
> since the car length decreases in the same proportion as the garage length decreases (from the pov of the garage observer and the car observer, respectively), both observers would deny, given the initial condition, that the car can perfectly fits in the garage. AG
On Fri, Dec 6, 2024 at 12:10 AM Alan Grayson <agrays...@gmail.com> wrote:>> from the garage man's POV the garage's length does not shrink but the car's length does. In Special Relativity time is diluted by the factor γ which is equal to 1 / √(1 - v²/c²) ; and an object's length will be reduced by a factor of the inverse of γ. So Length contraction reduces the length by 1/γ, and Time Dilation increases the time interval by γ. For example, at 87% the speed of light length contracts to half its original rest length, and time dilutes by a factor of two.The bottom line is that when two observers are in relative motion, like the garage man and the car driver are, they measure space and time differently. An event has a position and a time, and the closing of both garage doors is an event, so they will not agree if that event happened simultaneously when the entire car was in the garage or not.
> I don't think your proposed solution works. We're assuming the rest frame length of the car is larger than the rest frame length of the garage.As Jesse Mazer points out, if the car fits in the car driver's frame of reference then it always fits in the garage man's frame of reference. However if it doesn't fit in the garage men's frame of reference then it won't fit in the driver's frame of reference either; this can happen if the car is not going fast enough, and the asymmetry between the two viewpoints occurs because when the car driver and the garage man and the car and the garage are all in the same frame of reference (a.k.a. they are not moving with respect to each other) then they both agree that the car is longer than the garage. So there is never a contradiction, there is never an occasion where one of them predicts the car will fit in the garage and the other predicts it will not.
On Fri, Dec 6, 2024 at 7:45 AM John Clark <johnk...@gmail.com> wrote:On Fri, Dec 6, 2024 at 12:10 AM Alan Grayson <agrays...@gmail.com> wrote:>> from the garage man's POV the garage's length does not shrink but the car's length does. In Special Relativity time is diluted by the factor γ which is equal to 1 / √(1 - v²/c²) ; and an object's length will be reduced by a factor of the inverse of γ. So Length contraction reduces the length by 1/γ, and Time Dilation increases the time interval by γ. For example, at 87% the speed of light length contracts to half its original rest length, and time dilutes by a factor of two.The bottom line is that when two observers are in relative motion, like the garage man and the car driver are, they measure space and time differently. An event has a position and a time, and the closing of both garage doors is an event, so they will not agree if that event happened simultaneously when the entire car was in the garage or not.
> I don't think your proposed solution works. We're assuming the rest frame length of the car is larger than the rest frame length of the garage.As Jesse Mazer points out, if the car fits in the car driver's frame of reference then it always fits in the garage man's frame of reference.
However if it doesn't fit in the garage men's frame of reference then it won't fit in the driver's frame of reference either; this can happen if the car is not going fast enough, and the asymmetry between the two viewpoints occurs because when the car driver and the garage man and the car and the garage are all in the same frame of reference (a.k.a. they are not moving with respect to each other) then they both agree that the car is longer than the garage. So there is never a contradiction, there is never an occasion where one of them predicts the car will fit in the garage and the other predicts it will not.You didn't really answer my question before about whether you think there is any way to define the phrase "fits in the garage" in a way that doesn't involve questions of simultaneity.
If we do use a definition involving simultaneity, the natural one is to look at the two localized events A="back end of the car passes by the front door of garage" and B="front end of the car crashes into back wall of garage" (assuming the car does not brake so that everything is inertial up to the moment of the crash). In a frame where the crash B happens *after* the back end of the car entering the garage A, there will be some interval of time where the car is fully inside the garage and it hasn't yet crashed. In a frame where B happens *before* A, the car never fit in the garage because the front end crashed into the back wall before the back end had entered the garage.When you say there is never a contradiction,
> When you say there is never a contradiction, do you deny we can pick values for the rest length of the car and garage and their relative velocity such if we use the Lorentz transformation, we find that B happens before A in the car rest frame (so the car doesn't fit in that frame), but A happens before B in the garage rest frame (so the car does fit in that frame)? Or do you accept that point, but think there is some other way to define the notion of "fits in the garage" that doesn't involve questions of simultaneity?
On Friday, December 6, 2024 at 11:13:36 AM UTC-7 Jesse Mazer wrote:On Fri, Dec 6, 2024 at 7:45 AM John Clark <johnk...@gmail.com> wrote:On Fri, Dec 6, 2024 at 12:10 AM Alan Grayson <agrays...@gmail.com> wrote:>> from the garage man's POV the garage's length does not shrink but the car's length does. In Special Relativity time is diluted by the factor γ which is equal to 1 / √(1 - v²/c²) ; and an object's length will be reduced by a factor of the inverse of γ. So Length contraction reduces the length by 1/γ, and Time Dilation increases the time interval by γ. For example, at 87% the speed of light length contracts to half its original rest length, and time dilutes by a factor of two.The bottom line is that when two observers are in relative motion, like the garage man and the car driver are, they measure space and time differently. An event has a position and a time, and the closing of both garage doors is an event, so they will not agree if that event happened simultaneously when the entire car was in the garage or not.
> I don't think your proposed solution works. We're assuming the rest frame length of the car is larger than the rest frame length of the garage.As Jesse Mazer points out, if the car fits in the car driver's frame of reference then it always fits in the garage man's frame of reference.I think your claim is mistaken if you're using simultaneity in the car's frame. If not, then how do you define "fits in the garage"? See my comments in reply to Jesse. AGHowever if it doesn't fit in the garage men's frame of reference then it won't fit in the driver's frame of reference either; this can happen if the car is not going fast enough, and the asymmetry between the two viewpoints occurs because when the car driver and the garage man and the car and the garage are all in the same frame of reference (a.k.a. they are not moving with respect to each other) then they both agree that the car is longer than the garage. So there is never a contradiction, there is never an occasion where one of them predicts the car will fit in the garage and the other predicts it will not.You didn't really answer my question before about whether you think there is any way to define the phrase "fits in the garage" in a way that doesn't involve questions of simultaneity.Offhand, I don't know how else to structure a replywithout relying on simultaneity, but using simultaneity is useless since the garage observer will not agree with the car observer that the car fits in the garage, since he does not interpret simultaneity as the car observer does. And, in addition, the garage observer knows that the car's length decreases in the exact same proportion as the garage's length decreases, so he will deny that car fits since the relative lengths haven't changed, regardless of the car's velocity. AG
If we do use a definition involving simultaneity, the natural one is to look at the two localized events A="back end of the car passes by the front door of garage" and B="front end of the car crashes into back wall of garage" (assuming the car does not brake so that everything is inertial up to the moment of the crash). In a frame where the crash B happens *after* the back end of the car entering the garage A, there will be some interval of time where the car is fully inside the garage and it hasn't yet crashed. In a frame where B happens *before* A, the car never fit in the garage because the front end crashed into the back wall before the back end had entered the garage.When you say there is never a contradiction,I don't recall writing that; nor do I agree with that claim. I am saying that using simultaneity doesn't seem to solve the problem, since a solution must have both observers agree on an objective fact; whether the car fits or not. AG
Brent
On Friday, December 6, 2024 at 5:30:59 PM UTC-7 Brent Meeker wrote:
I thought I had put this to bed long ago. Here's how is looks in the cars reference frame. The garage ,which is 10' long, is moving fast toward the car. It's length is Lorentz contracted to only 6', so the car doesn't fit. No surprise since the car is 12' long.
But now from the garage's reference frame. The car is contracted to only 8' and so fits nicely, both ends of the car are inside the garage at the same time (where simultaneity is defined in the garage reference frame).
But doesn't this contradict the car's observation that the garage was way to short? No, because what the car measure to be simultaneous is shown as the slanted car. His front bumper was well beyond the end of the garage when his rear bumper had just entered. These two diagrams are just the Lorentz transform of one another.
Please elaborate on this point. TY, AG
Brent
So, from the car's frame, the car won't fit in garage due to contraction of garage's length, but from garage frame the car fits perfectly due to contraction of car's length, and then it doesn't?
So, apparently, there's no objective answer to the question of whether car fits in garage, or not. Doesn't there have to be agreement betweem the frames to claim the apparent paradox is resolved? BTW, what velcoity did you use to get the numerical contraction values? AG
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On 12/6/2024 6:09 PM, Alan Grayson wrote:
On Friday, December 6, 2024 at 5:30:59 PM UTC-7 Brent Meeker wrote:
I thought I had put this to bed long ago. Here's how is looks in the cars reference frame. The garage ,which is 10' long, is moving fast toward the car. It's length is Lorentz contracted to only 6', so the car doesn't fit. No surprise since the car is 12' long.
But now from the garage's reference frame. The car is contracted to only 8' and so fits nicely, both ends of the car are inside the garage at the same time (where simultaneity is defined in the garage reference frame).
But doesn't this contradict the car's observation that the garage was way to short? No, because what the car measure to be simultaneous is shown as the slanted car. His front bumper was well beyond the end of the garage when his rear bumper had just entered. These two diagrams are just the Lorentz transform of one another.
Please elaborate on this point. TY, AG
Brent
So, from the car's frame, the car won't fit in garage due to contraction of garage's length, but from garage frame the car fits perfectly due to contraction of car's length, and then it doesn't?How did you get "and then it doesn't out of what I wrote." Study the diagram.
Brent
On Friday, December 6, 2024 at 8:00:56 PM UTC-7 Brent Meeker wrote:
On 12/6/2024 6:09 PM, Alan Grayson wrote:
On Friday, December 6, 2024 at 5:30:59 PM UTC-7 Brent Meeker wrote:
I thought I had put this to bed long ago. Here's how is looks in the cars reference frame. The garage ,which is 10' long, is moving fast toward the car. It's length is Lorentz contracted to only 6', so the car doesn't fit. No surprise since the car is 12' long.
But now from the garage's reference frame. The car is contracted to only 8' and so fits nicely, both ends of the car are inside the garage at the same time (where simultaneity is defined in the garage reference frame).
But doesn't this contradict the car's observation that the garage was way to short? No, because what the car measure to be simultaneous is shown as the slanted car. His front bumper was well beyond the end of the garage when his rear bumper had just entered. These two diagrams are just the Lorentz transform of one another.
Please elaborate on this point. TY, AG
Brent
So, from the car's frame, the car won't fit in garage due to contraction of garage's length, but from garage frame the car fits perfectly due to contraction of car's length, and then it doesn't?How did you get "and then it doesn't out of what I wrote." Study the diagram.
BrentFirst the car doesn't fit from car's frame, then it does fit from garage frame, then the elogated car doesn't fit from garage frame. AG
On Friday, December 6, 2024 at 8:00:56 PM UTC-7 Brent Meeker wrote:
On 12/6/2024 6:09 PM, Alan Grayson wrote:
On Friday, December 6, 2024 at 5:30:59 PM UTC-7 Brent Meeker wrote:
I thought I had put this to bed long ago. Here's how is looks in the cars reference frame. The garage ,which is 10' long, is moving fast toward the car. It's length is Lorentz contracted to only 6', so the car doesn't fit. No surprise since the car is 12' long.
But now from the garage's reference frame. The car is contracted to only 8' and so fits nicely, both ends of the car are inside the garage at the same time (where simultaneity is defined in the garage reference frame).
But doesn't this contradict the car's observation that the garage was way to short? No, because what the car measure to be simultaneous is shown as the slanted car. His front bumper was well beyond the end of the garage when his rear bumper had just entered. These two diagrams are just the Lorentz transform of one another.
Please elaborate on this point. TY, AG
Brent
So, from the car's frame, the car won't fit in garage due to contraction of garage's length, but from garage frame the car fits perfectly due to contraction of car's length, and then it doesn't?How did you get "and then it doesn't out of what I wrote." Study the diagram.
Brent
First the car doesn't fit from car's frame, then it does fit from garage frame, then the elogated car doesn't fit from garage frame. AG
So, apparently, there's no objective answer to the question of whether car fits in garage, or not. Doesn't there have to be agreement betweem the frames to claim the apparent paradox is resolved? BTW, what velcoity did you use to get the numerical contraction values? AG
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On Friday, December 6, 2024 at 8:47:24 PM UTC-7 Alan Grayson wrote:
On Friday, December 6, 2024 at 8:00:56 PM UTC-7 Brent Meeker wrote:
On 12/6/2024 6:09 PM, Alan Grayson wrote:
On Friday, December 6, 2024 at 5:30:59 PM UTC-7 Brent Meeker wrote:
I thought I had put this to bed long ago. Here's how is looks in the cars reference frame. The garage ,which is 10' long, is moving fast toward the car. It's length is Lorentz contracted to only 6', so the car doesn't fit. No surprise since the car is 12' long.
But now from the garage's reference frame. The car is contracted to only 8' and so fits nicely, both ends of the car are inside the garage at the same time (where simultaneity is defined in the garage reference frame).
But doesn't this contradict the car's observation that the garage was way to short? No, because what the car measure to be simultaneous is shown as the slanted car. His front bumper was well beyond the end of the garage when his rear bumper had just entered. These two diagrams are just the Lorentz transform of one another.
Please elaborate on this point. TY, AG
Brent
So, from the car's frame, the car won't fit in garage due to contraction of garage's length, but from garage frame the car fits perfectly due to contraction of car's length, and then it doesn't?How did you get "and then it doesn't out of what I wrote." Study the diagram.
Brent
First the car doesn't fit from car's frame, then it does fit from garage frame, then the elogated car doesn't fit from garage frame. AG
Maybe you meant the elogated car doesn't fit in car frame, but we already knew this. AG
So, apparently, there's no objective answer to the question of whether car fits in garage, or not. Doesn't there have to be agreement betweem the frames to claim the apparent paradox is resolved? BTW, what velcoity did you use to get the numerical contraction values? AG
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On 12/6/2024 7:57 PM, Alan Grayson wrote:
On Friday, December 6, 2024 at 8:47:24 PM UTC-7 Alan Grayson wrote:
On Friday, December 6, 2024 at 8:00:56 PM UTC-7 Brent Meeker wrote:On 12/6/2024 6:09 PM, Alan Grayson wrote:On Friday, December 6, 2024 at 5:30:59 PM UTC-7 Brent Meeker wrote:
I thought I had put this to bed long ago. Here's how is looks in the cars reference frame. The garage ,which is 10' long, is moving fast toward the car. It's length is Lorentz contracted to only 6', so the car doesn't fit. No surprise since the car is 12' long.
But now from the garage's reference frame. The car is contracted to only 8' and so fits nicely, both ends of the car are inside the garage at the same time (where simultaneity is defined in the garage reference frame).
But doesn't this contradict the car's observation that the garage was way to short? No, because what the car measure to be simultaneous is shown as the slanted car. His front bumper was well beyond the end of the garage when his rear bumper had just entered. These two diagrams are just the Lorentz transform of one another.Please elaborate on this point. TY, AGBrentSo, from the car's frame, the car won't fit in garage due to contraction of garage's length, but from garage frame the car fits perfectly due to contraction of car's length, and then it doesn't?How did you get "and then it doesn't out of what I wrote." Study the diagram.
BrentFirst the car doesn't fit from car's frame, then it does fit from garage frame, then the elogated car doesn't fit from garage frame. AGMaybe you meant the elogated car doesn't fit in car frame, but we already knew this. AGIn the words of Oliver Heaviside, "I've given you an argument. I'm not obliged to give you an understanding."
Brent
On Friday, December 6, 2024 at 9:24:06 PM UTC-7 Brent Meeker wrote:On 12/6/2024 7:57 PM, Alan Grayson wrote:On Friday, December 6, 2024 at 8:47:24 PM UTC-7 Alan Grayson wrote:On Friday, December 6, 2024 at 8:00:56 PM UTC-7 Brent Meeker wrote:On 12/6/2024 6:09 PM, Alan Grayson wrote:On Friday, December 6, 2024 at 5:30:59 PM UTC-7 Brent Meeker wrote:
I thought I had put this to bed long ago. Here's how is looks in the cars reference frame. The garage ,which is 10' long, is moving fast toward the car. It's length is Lorentz contracted to only 6', so the car doesn't fit. No surprise since the car is 12' long.
But now from the garage's reference frame. The car is contracted to only 8' and so fits nicely, both ends of the car are inside the garage at the same time (where simultaneity is defined in the garage reference frame).
But doesn't this contradict the car's observation that the garage was way to short? No, because what the car measure to be simultaneous is shown as the slanted car. His front bumper was well beyond the end of the garage when his rear bumper had just entered. These two diagrams are just the Lorentz transform of one another.Please elaborate on this point. TY, AGBrentSo, from the car's frame, the car won't fit in garage due to contraction of garage's length, but from garage frame the car fits perfectly due to contraction of car's length, and then it doesn't?How did you get "and then it doesn't out of what I wrote." Study the diagram.
BrentFirst the car doesn't fit from car's frame, then it does fit from garage frame, then the elogated car doesn't fit from garage frame. AGMaybe you meant the elogated car doesn't fit in car frame, but we already knew this. AGIn the words of Oliver Heaviside, "I've given you an argument. I'm not obliged to give you an understanding."
BrentHeavyside isn't well known and now we know why. You can do better, much better, but don't want to. And that's where this story presumably ends. AG
On 12/6/2024 7:47 PM, Alan Grayson wrote:
On Friday, December 6, 2024 at 8:00:56 PM UTC-7 Brent Meeker wrote:
On 12/6/2024 6:09 PM, Alan Grayson wrote:
On Friday, December 6, 2024 at 5:30:59 PM UTC-7 Brent Meeker wrote:
I thought I had put this to bed long ago. Here's how is looks in the cars reference frame. The garage ,which is 10' long, is moving fast toward the car. It's length is Lorentz contracted to only 6', so the car doesn't fit. No surprise since the car is 12' long.
But now from the garage's reference frame. The car is contracted to only 8' and so fits nicely, both ends of the car are inside the garage at the same time (where simultaneity is defined in the garage reference frame).
But doesn't this contradict the car's observation that the garage was way to short? No, because what the car measure to be simultaneous is shown as the slanted car. His front bumper was well beyond the end of the garage when his rear bumper had just entered. These two diagrams are just the Lorentz transform of one another.
Please elaborate on this point. TY, AG
Brent
So, from the car's frame, the car won't fit in garage due to contraction of garage's length, but from garage frame the car fits perfectly due to contraction of car's length, and then it doesn't?How did you get "and then it doesn't out of what I wrote." Study the diagram.
Brent
First the car doesn't fit from car's frame, then it does fit from garage frame, then the elogated car doesn't fit from garage frame. AG
Maybe you don't know the difference between a space/time diagram and a space/space diagram.
Brent
On Friday, December 6, 2024 at 9:22:33 PM UTC-7 Brent Meeker wrote:
On 12/6/2024 7:47 PM, Alan Grayson wrote:
On Friday, December 6, 2024 at 8:00:56 PM UTC-7 Brent Meeker wrote:
On 12/6/2024 6:09 PM, Alan Grayson wrote:
On Friday, December 6, 2024 at 5:30:59 PM UTC-7 Brent Meeker wrote:
I thought I had put this to bed long ago. Here's how is looks in the cars reference frame. The garage ,which is 10' long, is moving fast toward the car. It's length is Lorentz contracted to only 6', so the car doesn't fit. No surprise since the car is 12' long.
But now from the garage's reference frame. The car is contracted to only 8' and so fits nicely, both ends of the car are inside the garage at the same time (where simultaneity is defined in the garage reference frame).
But doesn't this contradict the car's observation that the garage was way to short? No, because what the car measure to be simultaneous is shown as the slanted car. His front bumper was well beyond the end of the garage when his rear bumper had just entered. These two diagrams are just the Lorentz transform of one another.
Please elaborate on this point. TY, AG
Brent
So, from the car's frame, the car won't fit in garage due to contraction of garage's length, but from garage frame the car fits perfectly due to contraction of car's length, and then it doesn't?How did you get "and then it doesn't out of what I wrote." Study the diagram.
Brent
First the car doesn't fit from car's frame, then it does fit from garage frame, then the elogated car doesn't fit from garage frame. AG
Maybe you don't know the difference between a space/time diagram and a space/space diagram.
BrentI can read English well and what you've presented is a space/TIME diagram, with TIME on the vertical axis, and where the car perfectly fits from the pov of the garage, and then you have the enlongated car which doesn't fit, supposedly based on simultaneity as measured in the car's frame, which, as I previously wrote, we already know doesn't fit. I have a high IQ but absolutely no clue what you have proven, if anything. AG
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I've already explained it to you last month, there is no contradiction, just non agreement on simultaneity... from the cars pov, the doors aren't closed simultaneously, that's it.
I've already explained it to you last month, there is no contradiction, just non agreement on simultaneity... from the cars pov, the doors aren't closed simultaneously, that's it.
>> In the words of Oliver Heaviside, "I've given you an argument. I'm not obliged to give you an understanding."
Brent> Heavyside isn't well known
> What we have are two frames which reach opposiite conclusions about whether the car can fit in the garage.
> This seems paradoxical to me, but perhaps I am mistaken.
On Sat, Dec 7, 2024 at 1:43 PM Alan Grayson <agrays...@gmail.com> wrote:> What we have are two frames which reach opposiite conclusions about whether the car can fit in the garage.If that is true then Special Relativity is nonsense, and so is General Relativity because it is built on that foundation. But physicists tell me neither idea is nonsense and I find the argument they present to defend their view to be very VERY persuasive.
> This seems paradoxical to me, but perhaps I am mistaken.Either Einstein was wrong in 1905 and all professional physicists for the last 120 years have been wrong in accepting Einstein's argument, or you Alan Grayson are correct and have found a flaw that nobody in the last 120 years had noticed before. Which do you honestly think is more probable?
John K Clark pnt
On Saturday, December 7, 2024 at 3:51:30 AM UTC-7 Alan Grayson wrote:On Wednesday, December 4, 2024 at 2:41:25 PM UTC-7 Jesse Mazer wrote:On Wed, Dec 4, 2024 at 4:06 PM Alan Grayson <agrays...@gmail.com> wrote:In the case of a car whose rest length is greater than the length of the garage, from pov of the garage, the car will fit inside if its speed is sufficient fast due to length contraction of the car. But from the pov of the moving car, the length of garage will contract, as close to zero as one desires as its velocity approaches c, so the car will NOT fit inside the garage. Someone posted a link to an article which claimed, without proof, that this apparent contradiction can be resolved by the fact that simultaneity is frame dependent. I don't see how disagreements of simultaneity between frames solves this apparent paradox. AGCan you think of any way to define the meaning of the phrase "fit inside" other than by saying that the back end of the car is at a position inside the garage past the entrance "at the same time" as the front end of the car is at a position inside the garage but hasn't hit the back wall? (or hasn't passed through the back opening of the garage, if we imagine the garage as something like a covered bridge that's open on both ends) This way of defining it obviously depends on simultaneity, so different frames can disagree about whether there is any moment where such an event on the worldline of the back of the car is simultaneous with such an event on the worldline of the front of the car.
JesseAre you claiming that the apparent paradox can be resolved by accepting the fact that the car and garage frames have different conclusions about whether the car fits in the garage? AG
Let me restate the problem where the car length is assumed to be longer than the garage length in the rest frame. So, the car can never fit in the garage when moving, since the garage length, which is initially smaller than the car's length, contracts. So there's no possibility of a perfect fit within the garage where simultaneity would apply. However, the car can fit in the garage, from the garage frame, since the car's length contracts. So, we have a situation where the car fits in the garage, but only from the garage frame. This seems paradoxical insofar as there's no objective reality of whether the car fits in the garage or not. AG
On Fri, Dec 6, 2024 at 11:32 PM Alan Grayson <agrays...@gmail.com> wrote:>> In the words of Oliver Heaviside, "I've given you an argument. I'm not obliged to give you an understanding."
Brent> Heavyside isn't well knownPerhaps not on Twitter, but Oliver Heaviside is certainly well known and respected among professional physicists!
On Sat, Dec 7, 2024 at 1:43 PM Alan Grayson <agrays...@gmail.com> wrote:> What we have are two frames which reach opposiite conclusions about whether the car can fit in the garage.If that is true then Special Relativity is nonsense, and so is General Relativity because it is built on that foundation. But physicists tell me neither idea is nonsense and I find the argument they present to defend their view to be very VERY persuasive.
> two frames which reach opposite conclusions about whether the car can fit in the garage!
> Why is this so hard to understand?
On Sun, Dec 8, 2024 at 7:39 PM Alan Grayson <agrays...@gmail.com> wrote:> two frames which reach opposite conclusions about whether the car can fit in the garage!Yes but disagreeing about how long something is is the inevitable consequence of disagreeing about simultaneity. And after the thought experiment is over and the car slows down so it's in the same frame of reference as the garage there is no evidence of any paradox having occurred, there would be one if one observed the car making a big hole in the back door and the other did not, but nobody observed such a thing.
> Why is this so hard to understand?Because it's very hard to understand something if it's not true. I think I'll repeat what I said before:"Either Einstein was wrong in 1905 and all professional physicists for the last 120 years have been wrong in accepting Einstein's argument, or you Alan Grayson are correct and have found a flaw that nobody in the last 120 years had noticed before. Which do you honestly think is more probable?"
> This is nonsense. [...] Obviously, the paradox exists only when the car speeds up, to a sufficient speed so it can fit exactly in the garage.which you refuse to admit.
hr
On Mon, Dec 9, 2024 at 3:55 AM Alan Grayson <agrays...@gmail.com> wrote:> This is nonsense. [...] Obviously, the paradox exists only when the car speeds up, to a sufficient speed so it can fit exactly in the garage.which you refuse to admit.I admit that in different frames of reference clocks running at different speeds and meter-sticks having different lengths is odd,
> Since the contracted length of the car, from the pov of the garage, can be arbitraily close to zero, as v --> c, there's no way that the car cannot fit in the garage, from the pov of the garage. But from the pov of the car, assumed to have length greater than the garage as an initial condition, the car can never be contained within the garage, as the garage length shrinks.
1If that's your present position, why, when I first stated that the frames differed on whether the car will fit in the garage, did you claim the alleged flaw I described, would, if true, undermine 120 years of professional thinking about relativity? That is, why did you think I described a logical inconsistency or paradox, when now you've made a 180 degree turn on its implication? AG
On Monday, December 9, 2024 at 7:17:07 AM UTC-7 John Clark wrote:> If that's your present position,For heaven sake! Nobody is denying that two observers in two different frames of reference can and will observe different things and thus disagree if the car was ever entirely in the garage or not; just as they disagree about how long a meter stick is and how fast a clock ticks. But that's not a logical paradox, that's just strange. And objective reality does exist in relativity because some things DO remain constant in ANY frame of reference, such as the speed of light and the distance through spacetime of ANY two events.An event, such as the closing of both the front and back doors of the garage, is a specific point in space and time, the contraction of length and the stretching of time are not independent properties; they always change in such a way that the garage man in the car driver agree that the distance through spacetime between the front of the car entering the front of the garage in the back of the car exiting the back of the garage is exactly the same. But because they disagreed about length and time (but not when both are considered together) they will sometimes disagree if there was ever a time when both doors were closed AND the front and the back of the car were both in the garage.John K Clark1
> why, when I first stated that the frames differed on whether the car will fit in the garage, did you claim the alleged flaw I described, would, if true, undermine 120 years of professional thinking about relativity?
> now you've made a 180 degree turn on its implication
tst
tst
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On Monday, December 9, 2024 at 2:01:28 PM UTC-7 Brent Meeker wrote:
Since the car's length can be assumed to be arbitrarily small from the
pov of the garage, why worry about fitting the car in garage perfectly,and then appealing to difference in spontaneity to prove no directcontradiction between the frames? It seems like a foolish effort to
avoid a contradition, when one clearly exists. AG
On Monday, December 9, 2024 at 4:54:34 PM UTC-7 Brent Meeker wrote:
On 12/9/2024 3:24 PM, Alan Grayson wrote:
On Monday, December 9, 2024 at 2:01:28 PM UTC-7 Brent Meeker wrote:
>
> Nothing odd about dilation and contraction when you know its cause.
> But what is odd is the fact that each frame sees the result
> differently -- that the car fits in one frame, but not in the other --
> and you see nothing odd about that, that there's no objective reality
> despite the symmetry. AG
The facts are events in spacetime. There's an event F at which the
front of the car is even with the exit of the garage and there's an
event R at which the rear of the car is even with the entrance to the
garage. If R is before F we say the car fitted in the garage. If R is
after F we say the car did not fit. But if F and R are spacelike, then
there is no fact of the matter about their time order. The time order
will depend on the state of motion.
Brent
Since the car's length can be assumed to be arbitrarily small from thepov of the garage, why worry about fitting the car in garage perfectly,and then appealing to difference in spontaneity to prove no directcontradiction between the frames? It seems like a foolish effort toavoid a contradition, when one clearly exists. AG
What's the contradiction?ISTM that the car can, or cannot fit in garage given the initial condition that in the rest frame, the car is longer than the garage; in other words there is an objective reality, but the frames differ on whether the car fits or not.
If one avoids the issue of simultaneity, by not requiring the car to perfectly fit in the garage, we get opposite conclusions from the frames. AG
If one avoids the issue of simultaneity, by not requiring the car to perfectly fit in the garage, we get opposite conclusions from the frames. AGThe paradox does not depend on the assumption that the car is the same length as the garage in either the car frame or the garage frame (or that they have the same rest length),
if that's what you mean by "perfectly fit in the garage". Even if the car's rest length is much shorter than the garage's rest length, so it fits easily in the garage frame,
you could always pick a sufficiently large relative velocity such that the car would be longer than the garage in the car's rest frame,
and thus it would not fit in that frame, so the paradox remains. Not sure what "opposite conclusions from the frames" could mean if you don't have a specific way to define "fits in the garage" in a way that doesn't depend on picking some frame or another.
Jesse
Brent
If car exactly fits, this is ambiguous from the pov of garage frame due to lack of simultaneity, and this is the consensus solution to an alleged paradox. But what happens if the car's velocity is increased, so car fits with room to spare? This is the case I have been posting about. AGIf one avoids the issue of simultaneity, by not requiring the car to perfectly fit in the garage, we get opposite conclusions from the frames. AGThe paradox does not depend on the assumption that the car is the same length as the garage in either the car frame or the garage frame (or that they have the same rest length),I don't make this assumption. AG
if that's what you mean by "perfectly fit in the garage". Even if the car's rest length is much shorter than the garage's rest length, so it fits easily in the garage frame,No, this isn't the initial assumed car length. Its length is assumed larger than the garage, and the question is whether it can fit due to its motion which causes length contraction. AG
you could always pick a sufficiently large relative velocity such that the car would be longer than the garage in the car's rest frame,No, the car's length decreases in the garage frame only due to its motion. In the car's frame, the car's length doesn't change. AG
and thus it would not fit in that frame, so the paradox remains. Not sure what "opposite conclusions from the frames" could mean if you don't have a specific way to define "fits in the garage" in a way that doesn't depend on picking some frame or another.JesseAs I understand the problem, in the initial rest frame the car is assumed to be larger than the garage. Then the question is whether it can fit when the car is in motion due to length contraction. In the car's frame, the garage length decreases, so there is no possibility of the car fitting. OTOH, from the pov of the garage frame, the car's length shrinks, so there is some velocity where it fits perfectly. If the velocity continues to increase, the car fits with room to spare. So, I have shown that the frames differ in concluding whether the car fits, or not, and the question is whether this is a paradox. If you conclude it is not, then you deny there's an objective reality such that the car fits, or doesn't fit. And "fits" just means the car's contracted length is EQUAL TO or LESS than the garage's length. AG
On Monday, December 9, 2024 at 4:54:34 PM UTC-7 Brent Meeker wrote:
On 12/9/2024 3:24 PM, Alan Grayson wrote:
On Monday, December 9, 2024 at 2:01:28 PM UTC-7 Brent Meeker wrote:
>
> Nothing odd about dilation and contraction when you know its cause.
> But what is odd is the fact that each frame sees the result
> differently -- that the car fits in one frame, but not in the other --
> and you see nothing odd about that, that there's no objective reality
> despite the symmetry. AG
The facts are events in spacetime. There's an event F at which the
front of the car is even with the exit of the garage and there's an
event R at which the rear of the car is even with the entrance to the
garage. If R is before F we say the car fitted in the garage. If R is
after F we say the car did not fit. But if F and R are spacelike, then
there is no fact of the matter about their time order. The time order
will depend on the state of motion.
Brent
Since the car's length can be assumed to be arbitrarily small from thepov of the garage, why worry about fitting the car in garage perfectly,and then appealing to difference in spontaneity to prove no directcontradiction between the frames? It seems like a foolish effort toavoid a contradition, when one clearly exists. AG
What's the contradiction?The contradiction is precisely this; assuming the initial rest state is that the length of the car is larger than the length of the garage, we get the car never fitting in the garage from the pov of the car, and the car fitting in the garage from the pov of the garage. The car can't fit and not fit in the garage.
Further, the issue of simultaneity is a non-issue, since measurements of the front and back end of the car occur in the car's frame, and since the car never fits in the garage, such measurements can never be made when the car perfectly fits in the garage, or even loosely, since this condition never occurs.
you could always pick a sufficiently large relative velocity such that the car would be longer than the garage in the car's rest frame,No, the car's length decreases in the garage frame only due to its motion. In the car's frame, the car's length doesn't change. AGI didn't say the car's length changed in the car's frame, I just said that if you pick a sufficiently high relative velocity, then in the car's rest frame the car will be longer than the garage (in this case due to the garage's length being shortened in that frame).
and thus it would not fit in that frame, so the paradox remains. Not sure what "opposite conclusions from the frames" could mean if you don't have a specific way to define "fits in the garage" in a way that doesn't depend on picking some frame or another.JesseAs I understand the problem, in the initial rest frame the car is assumed to be larger than the garage. Then the question is whether it can fit when the car is in motion due to length contraction. In the car's frame, the garage length decreases, so there is no possibility of the car fitting. OTOH, from the pov of the garage frame, the car's length shrinks, so there is some velocity where it fits perfectly. If the velocity continues to increase, the car fits with room to spare. So, I have shown that the frames differ in concluding whether the car fits, or not, and the question is whether this is a paradox. If you conclude it is not, then you deny there's an objective reality such that the car fits, or doesn't fit. And "fits" just means the car's contracted length is EQUAL TO or LESS than the garage's length. AGYes, I've said before that there's no objective frame-independent reality about whether the car fits, that's part of the standard answer to this paradox. Do you accept that this is a valid way of resolving it? You seemed to be objecting in your earlier comment when you said "ISTM that the car can, or cannot fit in garage given the initial condition that in the rest frame, the car is longer than the garage; in other words there is an objective reality, but the frames differ on whether the car fits or not", but maybe I misunderstood?Jesse
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>> My conclusion is that there's a contradiction in evidence, since the situation of the car fitting and not fitting makes no sense. AG
>>And the answer only lies in disagreement of simultaneity of both doors being closed and the car fully inside the garage, and that is dependent on the frame of reference, there aren't any contradictions.
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Le mar. 10 déc. 2024, 19:31, Alan Grayson <agrays...@gmail.com> a écrit :On Tuesday, December 10, 2024 at 11:07:25 AM UTC-7 Alan Grayson wrote:On Tuesday, December 10, 2024 at 6:29:25 AM UTC-7 John Clark wrote:On Tue, Dec 10, 2024 at 5:47 AM Quentin Anciaux <allc...@gmail.com> wrote:>> My conclusion is that there's a contradiction in evidence, since the situation of the car fitting and not fitting makes no sense. AG>>And the answer only lies in disagreement of simultaneity of both doors being closed and the car fully inside the garage, and that is dependent on the frame of reference, there aren't any contradictions.Exactly! In Special Relativity two observers in different frames of reference can disagree about what order a series of events should be in, provided that the events are "spacelike separated", that is to say if even the speed of light is not fast enough to send a signal between them. One observer could say events should be ordered XYZ and another insist the order should be XZY. The classic example is two lightning strikes hitting the front and back of a very fast moving train, an observer on the train might see them as simultaneous but an observer on the ground see one hit happening before the other.And in the example that Alan has trouble with, one observer might say the back of the car entered the garage before the back door of the garage was opened, and another observer in a different frame of reference would say that happened after the back door of the garage was opened. So one would say the car was able to fit into the garage and the other would say it could not.John K ClarkApparently you haven't read my posts or don't understand them. If the initial conditions are set so the car's length is longer than the garage, and then the car is set in motion, the car is NEVER inside the garage since the garage is contracting! In this situation, there would be no measurements that you allege for which simultaneity would apply. There is NO entering of the garage for the car! AGFurther, you bring up spacelike separated events to allegedly make your points. But as far as I can tell, no events in this situation are spacelike separated. AGSo the front door, the back door, the front of the car, the rear of the car are all at the same spacelike location? I don't call that doors or cars, I call that a point, and there are no paradoxes
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Le mar. 10 déc. 2024, 19:42, Alan Grayson <agrays...@gmail.com> a écrit :On Tuesday, December 10, 2024 at 11:36:19 AM UTC-7 Quentin Anciaux wrote:Le mar. 10 déc. 2024, 19:31, Alan Grayson <agrays...@gmail.com> a écrit :On Tuesday, December 10, 2024 at 11:07:25 AM UTC-7 Alan Grayson wrote:On Tuesday, December 10, 2024 at 6:29:25 AM UTC-7 John Clark wrote:On Tue, Dec 10, 2024 at 5:47 AM Quentin Anciaux <allc...@gmail.com> wrote:>> My conclusion is that there's a contradiction in evidence, since the situation of the car fitting and not fitting makes no sense. AG>>And the answer only lies in disagreement of simultaneity of both doors being closed and the car fully inside the garage, and that is dependent on the frame of reference, there aren't any contradictions.Exactly! In Special Relativity two observers in different frames of reference can disagree about what order a series of events should be in, provided that the events are "spacelike separated", that is to say if even the speed of light is not fast enough to send a signal between them. One observer could say events should be ordered XYZ and another insist the order should be XZY. The classic example is two lightning strikes hitting the front and back of a very fast moving train, an observer on the train might see them as simultaneous but an observer on the ground see one hit happening before the other.And in the example that Alan has trouble with, one observer might say the back of the car entered the garage before the back door of the garage was opened, and another observer in a different frame of reference would say that happened after the back door of the garage was opened. So one would say the car was able to fit into the garage and the other would say it could not.John K ClarkApparently you haven't read my posts or don't understand them. If the initial conditions are set so the car's length is longer than the garage, and then the car is set in motion, the car is NEVER inside the garage since the garage is contracting! In this situation, there would be no measurements that you allege for which simultaneity would apply. There is NO entering of the garage for the car! AGFurther, you bring up spacelike separated events to allegedly make your points. But as far as I can tell, no events in this situation are spacelike separated. AGSo the front door, the back door, the front of the car, the rear of the car are all at the same spacelike location? I don't call that doors or cars, I call that a point, and there are no paradoxesYou don't get it. The car is never inside the garage, given the initial conditions. AGSomeone doesn't get it that's true, if somehow you could stop the I'm the genius versus the dumb world attitude, that'll surely help you, you have a big ego problem.
you could always pick a sufficiently large relative velocity such that the car would be longer than the garage in the car's rest frame,No, the car's length decreases in the garage frame only due to its motion. In the car's frame, the car's length doesn't change. AGI didn't say the car's length changed in the car's frame, I just said that if you pick a sufficiently high relative velocity, then in the car's rest frame the car will be longer than the garage (in this case due to the garage's length being shortened in that frame).I don't follow. If the garage's length is shorten, the length of the car remains unchanged. AG
and thus it would not fit in that frame, so the paradox remains. Not sure what "opposite conclusions from the frames" could mean if you don't have a specific way to define "fits in the garage" in a way that doesn't depend on picking some frame or another.JesseAs I understand the problem, in the initial rest frame the car is assumed to be larger than the garage. Then the question is whether it can fit when the car is in motion due to length contraction. In the car's frame, the garage length decreases, so there is no possibility of the car fitting. OTOH, from the pov of the garage frame, the car's length shrinks, so there is some velocity where it fits perfectly. If the velocity continues to increase, the car fits with room to spare. So, I have shown that the frames differ in concluding whether the car fits, or not, and the question is whether this is a paradox. If you conclude it is not, then you deny there's an objective reality such that the car fits, or doesn't fit. And "fits" just means the car's contracted length is EQUAL TO or LESS than the garage's length. AGYes, I've said before that there's no objective frame-independent reality about whether the car fits, that's part of the standard answer to this paradox. Do you accept that this is a valid way of resolving it? You seemed to be objecting in your earlier comment when you said "ISTM that the car can, or cannot fit in garage given the initial condition that in the rest frame, the car is longer than the garage; in other words there is an objective reality, but the frames differ on whether the car fits or not", but maybe I misunderstood?JesseMy conclusion is that there's a contradiction in evidence, since the situation of the car fitting and not fitting makes no sense. AG
From that it's concluded that from garage frame, it's indeterminate whether the car really fits. But I'm confused on this point. How can the garage frame know about those measurements in car frame, and know they differ? AG
On Monday, December 9, 2024 at 4:54:34 PM UTC-7 Brent Meeker wrote:
On 12/9/2024 3:24 PM, Alan Grayson wrote:
On Monday, December 9, 2024 at 2:01:28 PM UTC-7 Brent Meeker wrote:
>
> Nothing odd about dilation and contraction when you know its cause.
> But what is odd is the fact that each frame sees the result
> differently -- that the car fits in one frame, but not in the other --
> and you see nothing odd about that, that there's no objective reality
> despite the symmetry. AG
The facts are events in spacetime. There's an event F at which the
front of the car is even with the exit of the garage and there's an
event R at which the rear of the car is even with the entrance to the
garage. If R is before F we say the car fitted in the garage. If R is
after F we say the car did not fit. But if F and R are spacelike, then
there is no fact of the matter about their time order. The time order
will depend on the state of motion.
Brent
Since the car's length can be assumed to be arbitrarily small from thepov of the garage, why worry about fitting the car in garage perfectly,and then appealing to difference in spontaneity to prove no directcontradiction between the frames? It seems like a foolish effort toavoid a contradition, when one clearly exists. AG
What's the contradiction?
The contradiction is precisely this; assuming the initial rest state is that the length of the car is larger than the length of the garage, we get the car never fitting in the garage from the pov of the car, and the car fitting in the garage from the pov of the garage. The car can't fit and not fit in the garage.
The former result is easy to see, since the car's motion shrinks the garage's length, so the car, initially longer than the garage, can never fit inside the garage.
The latter result follows from the fact that from the pov of the garage, the car's length shrinks, and for a sufficient velocity, it will shrink enough to fit in the garage. Further, the issue of simultaneity is a non-issue,
since measurements of the front and back end of the car occur in the car's frame, and since the car never fits in the garage, such measurements can never be made when the car perfectly fits in the garage, or even loosely, since this condition never occurs. In summary, I think I've done for relativity, what Bertrand Russell did for Cantor's set theory; proving the existence of a contradiction. AG
Brent
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The former result is easy to see, since the car's motion shrinks the garage's length, so the car, initially longer than the garage, can never fit inside the garage.Within the cars reference frame.
The latter result follows from the fact that from the pov of the garage, the car's length shrinks, and for a sufficient velocity, it will shrink enough to fit in the garage. Further, the issue of simultaneity is a non-issue,No it is the essential issue. The car (or the garage) don't actually undergo some physical shrinkage.
If they did they wouldn't keep their dimensions in their own frame. So it is a question of measurement and simultaneity.
If they did they wouldn't keep their dimensions in their own frame. So it is a question of measurement and simultaneity.Why then do physicists agree that the distance to Andromeda will be immensely shortened if a traveler's velocity is close to c? Never a mention of simultaneiry in this case. AG
On 12/10/2024 10:07 AM, Alan Grayson wrote:
> Apparently you haven't read my posts or don't understand them. If the
> initial conditions are set so the car's length is longer than the
> garage, and then the car is set in motion, the car is NEVER inside the
> garage since the garage is contracting!
But in the garage's system the car is contracting!!
Brent
The former result is easy to see, since the car's motion shrinks the garage's length, so the car, initially longer than the garage, can never fit inside the garage.Within the cars reference frame.
Yes. AGThe latter result follows from the fact that from the pov of the garage, the car's length shrinks, and for a sufficient velocity, it will shrink enough to fit in the garage. Further, the issue of simultaneity is a non-issue,No it is the essential issue. The car (or the garage) don't actually undergo some physical shrinkage.
Yes. It's all about appearances, or so it seems.
And yet, physicists claim the LT gives the actual measurements in one frame, using the measurements in another frame. AGIf they did they wouldn't keep their dimensions in their own frame. So it is a question of measurement and simultaneity.
Why then do physicists agree that the distance to Andromeda will be immensely shortened if a traveler's velocity is close to c? Never a mention of simultaneiry in this case. AG
Brent
since measurements of the front and back end of the car occur in the car's frame, and since the car never fits in the garage, such measurements can never be made when the car perfectly fits in the garage, or even loosely, since this condition never occurs. In summary, I think I've done for relativity, what Bertrand Russell did for Cantor's set theory; proving the existence of a contradiction. AG
Brent
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The former result is easy to see, since the car's motion shrinks the garage's length, so the car, initially longer than the garage, can never fit inside the garage.Within the cars reference frame.
Yes. AGThe latter result follows from the fact that from the pov of the garage, the car's length shrinks, and for a sufficient velocity, it will shrink enough to fit in the garage. Further, the issue of simultaneity is a non-issue,No it is the essential issue. The car (or the garage) don't actually undergo some physical shrinkage.
Yes. It's all about appearances, or so it seems.No, it's all about measurements and simultaneity.
And yet, physicists claim the LT gives the actual measurements in one frame, using the measurements in another frame. AG
If they did they wouldn't keep their dimensions in their own frame. So it is a question of measurement and simultaneity.
Why then do physicists agree that the distance to Andromeda will be immensely shortened if a traveler's velocity is close to c? Never a mention of simultaneiry in this case. AG
Because they're not concerned with two events, just with the duration of the trip. In this case you must consider two events: One when the front of the car is adjacent to the exit of the garage and the other when the rear of the car is adjacent to the entrance of the garage. If these two events are spacelike relative to one another then there is a reference frame in which they are simultaneous.
Brent
Do I not only have provide a diagram I also have to explain it in detail just to end this silly thread??
On Tuesday, December 10, 2024 at 11:15:16 PM UTC-7 Brent Meeker wrote:Do I not only have provide a diagram I also have to explain it in detail just to end this silly thread??Yes you do. Providing plots without the numerical values in the LT, is useless. I can't tell if you're drawing plots to satisfy your biases, or if the numbers support the case you're making. Lesson learned; always do a real proof, which means supplying the arguments, or STFU. AG
First note by comparing the two diagrams that the car is longer than the garage, 12' vs 10'. So the car doesn't fit at small relative speed. What does "fit" mean? It means that the event of the front of the car coinciding with the right-hand end of the garage is after or at the same time as the rear of the car coinciding with the left-had end of the garage. In both diagrams the car is moving to the right at 0.8c so \gamma=sqrt{1-0.8^2}=0.6. Consequently, in the car's reference frame, the garage is contracted to 6' length and when the rear of the car is just entering the garage, the front is simultaneously, in the car's reference frame, already 6' beyond the right-hand end of the garage.
Then in the garage's reference frame the car's length is contracted to 0.6*12'=7.2' so at the moment the front of the car coincides with the right end of the garage, the rear of the car will simultaneously, in the garage reference system, be 2.8' inside the garage as shown below.
Note that in the above diagram I have marked two simultaneous events with small \delta's. The diagram below is just the Lorentz transform of the one above. The two simultaneous \delta's are also in the diagram below. You can confirm they are the same events by referring to the time blips along the world lines, which are also just the Lorentz transforms of those above. But clearly the events marking the simultaneous locations of the rear and front of the car above are NOT simultaneous in the garage frame below. Conversely, the front and rear simultaneous locations of the car below are not simultaneous in the above diagram, as the reader is invited to confirm by plotting them. Simultaneity is frame dependent.
Incidentally, when I was in graduate school this was still know as the "Tank Trap Paradox". The idea was that if one dug a tank trap shorter than the enemy tank, then the tank would just bridge the hole, UNLESS the tank were going very fast in which its contracted length would allow it to fall into the trap. This was being explained to me by Jurgen Ehlers, whom you may correctly infer from his name was a German professor recently hired at Univ Texas. I said, "What is it with you Germans, illustrating things with tank traps and cats in boxes with poison gas?" Jurgen who was too young to have fought in the war didn't realize I was pulling his leg and he was struck speechless.
Brent
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Le mer. 11 déc. 2024, 07:40, Alan Grayson <agrays...@gmail.com> a écrit :On Tuesday, December 10, 2024 at 11:15:16 PM UTC-7 Brent Meeker wrote:Do I not only have provide a diagram I also have to explain it in detail just to end this silly thread??Yes you do. Providing plots without the numerical values in the LT, is useless. I can't tell if you're drawing plots to satisfy your biases, or if the numbers support the case you're making. Lesson learned; always do a real proof, which means supplying the arguments, or STFU. AGWake up, your ego will kill your brain.
On Tuesday, December 10, 2024 at 11:51:46 PM UTC-7 Quentin Anciaux wrote:Le mer. 11 déc. 2024, 07:40, Alan Grayson <agrays...@gmail.com> a écrit :On Tuesday, December 10, 2024 at 11:15:16 PM UTC-7 Brent Meeker wrote:Do I not only have provide a diagram I also have to explain it in detail just to end this silly thread??Yes you do. Providing plots without the numerical values in the LT, is useless. I can't tell if you're drawing plots to satisfy your biases, or if the numbers support the case you're making. Lesson learned; always do a real proof, which means supplying the arguments, or STFU. AGWake up, your ego will kill your brain.I don't suppose you could explain the resolution clearly. Relying on slogans, which you have done throughout without knowing it, gets us nowhere. I am studying the numbers, and hoping this resolves the issue. AG
First note by comparing the two diagrams that the car is longer than the garage, 12' vs 10'. So the car doesn't fit at small relative speed. What does "fit" mean? It means that the event of the front of the car coinciding with the right-hand end of the garage is after or at the same time as the rear of the car coinciding with the left-had end of the garage. In both diagrams the car is moving to the right at 0.8c so \gamma=sqrt{1-0.8^2}=0.6. Consequently, in the car's reference frame, the garage is contracted to 6' length and when the rear of the car is just entering the garage, the front is simultaneously, in the car's reference frame, already 6' beyond the right-hand end of the garage.
Then in the garage's reference frame the car's length is contracted to 0.6*12'=7.2' so at the moment the front of the car coincides with the right end of the garage, the rear of the car will simultaneously, in the garage reference system, be 2.8' inside the garage as shown below.
Note that in the above diagram I have marked two simultaneous events with small \delta's. The diagram below is just the Lorentz transform of the one above. The two simultaneous \delta's are also in the diagram below. You can confirm they are the same events by referring to the time blips along the world lines, which are also just the Lorentz transforms of those above. But clearly the events marking the simultaneous locations of the rear and front of the car above are NOT simultaneous in the garage frame below. Conversely, the front and rear simultaneous locations of the car below are not simultaneous in the above diagram, as the reader is invited to confirm by plotting them. Simultaneity is frame dependent.
Incidentally, when I was in graduate school this was still know as the "Tank Trap Paradox". The idea was that if one dug a tank trap shorter than the enemy tank, then the tank would just bridge the hole, UNLESS the tank were going very fast in which its contracted length would allow it to fall into the trap. This was being explained to me by Jurgen Ehlers, whom you may correctly infer from his name was a German professor recently hired at Univ Texas. I said, "What is it with you Germans, illustrating things with tank traps and cats in boxes with poison gas?" Jurgen who was too young to have fought in the war didn't realize I was pulling his leg and he was struck speechless.
Brent
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