create unmanaged model to oracle view/synonym

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Fabio C. Barrionuevo da Luz

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31 déc. 2014, 11:05:0531/12/2014
à django...@googlegroups.com
Hello, is possible with Django 1.7 create a unmanaged Django model for Oracle database View?

I succeeded in doing this using sqlalchemy, However, would like to use Django and Django ORM.

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Fábio C. Barrionuevo da Luz
Acadêmico de Sistemas de Informação na Faculdade Católica do Tocantins - FACTO
Palmas - Tocantins - Brasil - América do Sul


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Shai

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1 janv. 2015, 11:40:4301/01/2015
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Hi Fábio,


On Wednesday, December 31, 2014 6:05:05 PM UTC+2, Fabio Caritas Barrionuevo da Luz wrote:
Hello, is possible with Django 1.7 create a unmanaged Django model for Oracle database View?



Yes. In your model's Meta, set managed to False and db_table to the view name:

class MyUnManagedModel(models.Model):
    # ...
    # fields
    # ...
    class Meta:
        managed = False
        db_table = 'view_name'

Have you run into difficulties?

HTH,
Shai.

Edgar Gabaldi

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1 janv. 2015, 14:57:3801/01/2015
à django...@googlegroups.com
Fabio,

Django ORM support Oracle Database[1].

If you want connect an existing oracle database, i recomend you see the inspectdb management command.



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Fabio Caritas Barrionuevo da Luz

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2 janv. 2015, 09:05:2402/01/2015
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Hello, Shai and Edgar

yes, I've tried using inspectdb, however, it only generates models for database tables, but not for database View[1] and database Synonym[2].

The Django documentation is currently not explicit in showing that the specific database features are supported by Django database backends.

inspectdb does not support "database schemas"[3][4].

Any other ideas how to solve this?




-- 
Fábio C. Barrionuevo da Luz
Acadêmico de Sistemas de Informação na Faculdade Católica do Tocantins - FACTO
Palmas - Tocantins - Brasil - América do Sul



Collin Anderson

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4 janv. 2015, 14:26:3304/01/2015
à django...@googlegroups.com
Hi,

What happens when you try Shai's suggestion?

class MyUnManagedModel(models.Model):
   
# ...
   
# fields
   
# ...
   
class Meta:
        managed
= False
        db_table
= 'view_name'

Collin

Sunil Naik

non lue,
16 févr. 2017, 07:34:3616/02/2017
à Django users
Thanks Collin, it worked for me.
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