How can I create a URL programmatically (e.g. without uri"some hard-coded string")?

[Emre Sevinc]

Hello,

According to Rapture I/O web page, it is possible to very easily create an URL to be slurped  when we have a hard-coded string, e.g.

 scala> uri"http://cnn.com"

 res17: rapture.net.HttpUrl = http://cnn.com/

But now let's assume I want to achieve the same effect, this time by passing a val, e.g. let's say I have:

   val src = "http://cnn.com/"

And I want to use this val instead of the hard-coded string to create the same rapture.net.HttpUrl object.

How can I do this?

[Jon Pretty]

Hi Emre,

You'll need to use the `Http.parse(myString)` method. This works on `http` and `https` resources, but not other URI schemes, so if you need to use something else, unfortunately you'll have to know the scheme in advance, or attempt the parsing with different companion objects (e.g. `File`).

Hope that helps!
Jon

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[Emre Sevinc]

Hello Jon,

Thanks for the quick help. Indeed, Http.parse nailed it! Thank you very much. (I only needed http and https resources, so this is perfectly fine for my use-case).

Cheers,

Emre

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Emre Sevinc