Dear Juan,
Pay far more attention to what Taff sends as that is likely to quickly yield you the results that you want.
I have no ability in SketchUp and am just beginning my enquiry into spherical triangles.
A few things that I have learnt so far are:
* A sphere always has a radius of 1. You get all the dimensions of the brick from this sphere and just multiply by the desired radius to get the final dimensions.
* Lengths are often stated as angles. Lengths are of arcs that extend that angle to the center of the sphere.
*You can choose the depth of the triangle at any stage. It can range from zero to the radius of the circle. So if you want to cover the surface of the sphere with a ferro-cement shell, the depth cpuld be 1 inch.If you want a convential brick, the depth could be 4 inches.
* The three angles that I sent you correspond to the following three sides of a spherical brick.
70.533 = 3.142*70.533/180 = 1.2311
54.733 = 3.142*54.733/180 = 0.95539
*None of the above would make any sense were it not for the fact that just 24 of these bricks cover the spherical surface completly and smoothly.
You can make a paprer model in about one hours time to see it for yourself.Or a model in SketchUp would show the same.
Still, these are very large bricks and you may want an alternate solution.
Wenninger has the following solution
20 degrees 54 minutes; 31 degrees 43 minutes and 37 degrees and 23 minutes
You need 120 of these bricks.Ten bricks make a pentagonal section and you need 12 of them to make the sphere.
No probleeem if you use Sketch Up.
Regards
Ashok