
Hi Matthew,
I'm glad that you find step-44 to be a useful tutorial! Let me
try to answer your questions directly.
My first question deals with the statement "The Euler-Lagrange equations corresponding to the residual"
Directly above this sentence is the residual, whose derivation I understand. Where I am lost is that s tact on to equations. I have only one residual equation. I cannot bridge that disconnect.
This is just another way of saying that the three equations
listed there (these E-L equations) are the strong form of the
governing equations. Basically, if you take each of these
equations (along the way, modifying the definition of the stress
in the equilibrium equation), test them with the appropriate test
function and sum up the three residual contributions then you
recover the (total) residual, or stationary point of the residual,
that is listed above. The point is that it not necessarily so
straight forward to go from the strong form to the weak form for
this mixed formulation, so identifying the conservation equations
a-postori is a helpful sanity check here. They seem to align with
what we're trying to do here.
I am completely lost here. What is the significance of p and J not having derivatives on them that makes it "easy" to solve for those terms in isolation?
Well, that's a valid point. I can't quite recall what exactly we
were trying to identify with this comment. I'll think about it, as
that seems to be a point that we could improve on in the
documentation. That there is no K_{pp} contribution is
significant, because it makes condensing out the p and J fields
easier. Maybe we meant to refer to the lack of contribution to
K_{pp} (as there is no second derivative involving a variation and
linearisation of p.
I am also confused how K_pJ, K_Jp and K_JJ form a block diagonal matrix. I could get there if I ignore the top row but then the equations below do not make sense I think. Some detail on this part of the process would be great.
So this is more easy to explain. We specifically choose discontinuous shape function to discretise these fields. As there are no interface/flux contributions, all local element contributions for these terms will remain local and you therefore end up with an assembled matrix for these contributions that has a block-like structure. The K_{JJ} matrix is evidently block-diagonal, as it is a field that couples with itself. As for the coupling matrices K_{pJ} and K_{Jp}, they are block-diagonal because we chose exactly the same discretisation for both fields (i.e. the shape functions and polynomial order match).
Does that make sense?
Best,
Jean-Paul
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