evaluate a string in the current scope

[G. M.-S.]

Is there a way to evaluate a string in the current scope?

So that

sage: expression

and

sage: some_evaluate(str(expression))

give the same thing at the same place.

I know about sage_eval, but it seems to need a dictionary of everything in the local scope.

For instance,

sage: a=3

sage: a^2

9

sage: some_evaluate('a^2')

9

instead of

sage: a=3

sage: sage_eval('a^2')

NameError: name 'a' is not defined

(of course this is a trivial example).

Guillermo

[Dima Pasechnik]

there is a plain eval():

sage: a=2
sage: eval("a^2")
0
sage: eval("a+a")
4
sage: eval("a**2")
4

(it looks like it doesn't do preparsing, but is the "normal" Python,
but it's a minor issue IMHO)

>
> Guillermo
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[G. M.-S.]

Thanks Dima.

I think that

sage: eval(preparse(string))

does what I need.

Guillermo