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On 2019-03-28 10:09 p.m., johnk wrote:
the FTC in the States started cracking down and said that any power
claims had to be based on teh RMS output (.707 of the peak) using a sine
wave with Specified distortion. AND that the unit had to be conditioned
at almost maximum power (75% if I recall, or Perhaps 90%)for several
minutes before taking the measurement. SOME units sudenly could not
show ANY power as the pre-conditioning was enough to cause them to shut
down or Melt down.
Well, how do I say this Thomas?
It is NOT to be called Watts RMS !
They left the vital word out – it is Watts [RMS derived]. They left out “derived”.
The RMS volts and RMS amps that you mention when multiplied together produce Watts. Just plain Watts.
These Watts are actually the average power of the power waveform that resulted from your two sinewaves.
Remember too, that the RMS value of the voltage waveform gives the DC voltage that provides the same heating effect. And that is average power.
Gee, I didn’t say that well. I have just spent a while fighting with Win 10 and drivers for CH340 on Arduino clone boards – I haven’t recovered !
You might think that I am nit picking. However you did say this, “RMS power of a sine wave is 0,5 times peak power.”
And the power waveform isn’t really a sinewave in the way we mean it. The values of interest here lie in the area under the curve (notice it is twice the frequency too?]. In a sine wave [like the Voltage one] the areas of interest are the equal sized ‘lobes’ above and below the zero line.
I invite you to draw out the two sinewaves [Volts and Current] and the resulting power waveform and perform an actual root-mean-square calculation on it to prove your statement. [Graphically is more reliable because it shows the workings J ]
Spoiler: you will NOT get 0.5 x pk as the answer.
The VERY rough sketch that I sent Charles shows what I mean about the average value [the green bit tipped over into the trough].
(Rough because I was on a new touch screen laptop and NOT in tablet mode. I was experimenting; made it tricky to draw with the pen. )
I know that you know what you mean when you refer to amplifiers this way, but you could add the extra word and be ‘more right’ J
Thanks for nibbling on the hook. But, I really do wish that someone had been willing to do the graphical maths thing. Someone must want to prove me wrong, surely.
John Kaesehagen
Australia
neoni...@googlegroups.com [mailto:neoni...@googlegroups.com] On Behalf Of Tomasz Kowalczyk
Sent: Tuesday, 16 April 2019 20:30
To: neonixie-l
Subject: Re: [neonixie-l] OT: audio levels
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Thomas, the audio levels standards do exist. But I agree with you that there isn’t just one.
Each of the areas has its own standard. So, you do have a known standard for consumer electronics. You do have known standards for radio/entertainment, studio and professional work [pre DAWs]. And you do have a ‘new’ standard for recent era digital equipments. That is why I mentioned Bob Katz’ book when Jens asked his question. I had to work with a Dutch mixing desk that attempted to be able to be employed in ‘both’ eras radio and recording studio environments. They didn’t manage it – they threw away a lot of head room. [Scorpius] The metering issues created extra problems because ideally you want the standards there to match the sensitivities too – but there is conflict. And it all depends whether you back the Loudness Wars. Remember too, generally you aren’t trying to make an equipment that is to serve in more than one of the environments.
I say – Long Live Dynamic Range !
John Kaesehagen
Australia
From: neoni...@googlegroups.com [mailto:neoni...@googlegroups.com] On Behalf Of Tomasz Kowalczyk
Sent: Tuesday, 16 April 2019 19:54
To: neonixie-l
Subject: Re: [neonixie-l] OT: audio levels
W dniu piątek, 29 marca 2019 08:46:37 UTC+1 użytkownik charles napisał:
On 2019-03-28 10:09 p.m., johnk wrote:
based on teh RMS output (.707 of the peak)
That would be 0,707 (1/sqrt(2)) voltage output on a resistive load. RMS power of a sine wave is 0,5 times peak power.
I like to know maximum constant RMS output, because it tells me a lot about the amplifier and its capability. The peak power or music power usually lacks a definition (I can easily imagine a design that would allow for short pulse of higher power, but power supply/amplifier would fry up if it was to deliver this peak power for longer time).
It is well known that for most time amplifier delivers a little percentage of its maximum power, but having continous Watts RMS into specified load rating is a very solid rating with solid definition.
On the topic: it really bothers me that there is no definition of one voltage standard. It would make perfect sense to create a standard of a CD output, for example - a 2Vpp signal, in which +1V would correspond to maximum digital value DAC can give (65535 for standard 16-bit) and -1V would correspond to a value of 0. It would make designing amplifiers much easier - the sensivity would be always same.
Currently I'm building a vacuum tube amplifier and I'm mad at the fact that I need to make the sensivity on 200mVpp level (my phone output), but most of other sources will have much higher signal. I think I'll need to go with a noisy method of applying extra resistor in series with volume potentiometer for the higher inputs... or apply the resistor and a "+20dB" switch that will short it.
At least it is a vacuum tube amplifier, so noise will be an issue anyway.
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Gee Whizz. Sorry for not spelling your name correctly in the two posts Tomasz.
That was very careless and rude of me – please accept my apologies.
John K
From: neoni...@googlegroups.com [mailto:neoni...@googlegroups.com] On Behalf Of Tomasz Kowalczyk
Sent: Tuesday, 16 April 2019 20:30
To: neonixie-l
Subject: Re: [neonixie-l] OT: audio levels
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Well, how do I say this Thomas?
It is NOT to be called Watts RMS !
They left the vital word out – it is Watts [RMS derived]. They left out “derived”.
The RMS volts and RMS amps that you mention when multiplied together produce Watts. Just plain Watts.
These Watts are actually the average power of the power waveform that resulted from your two sinewaves.
Remember too, that the RMS value of the voltage waveform gives the DC voltage that provides the same heating effect. And that is average power.
Gee, I didn’t say that well. I have just spent a while fighting with Win 10 and drivers for CH340 on Arduino clone boards – I haven’t recovered !
You might think that I am nit picking. However you did say this, “RMS power of a sine wave is 0,5 times peak power.”
And the power waveform isn’t really a sinewave in the way we mean it. The values of interest here lie in the area under the curve (notice it is twice the frequency too?]. In a sine wave [like the Voltage one] the areas of interest are the equal sized ‘lobes’ above and below the zero line.
I invite you to draw out the two sinewaves [Volts and Current] and the resulting power waveform and perform an actual root-mean-square calculation on it to prove your statement. [Graphically is more reliable because it shows the workings J ]
Spoiler: you will NOT get 0.5 x pk as the answer.
The VERY rough sketch that I sent Charles shows what I mean about the average value [the green bit tipped over into the trough].
(Rough because I was on a new touch screen laptop and NOT in tablet mode. I was experimenting; made it tricky to draw with the pen. )
I know that you know what you mean when you refer to amplifiers this way, but you could add the extra word and be ‘more right’ J
Thanks for nibbling on the hook. But, I really do wish that someone had been willing to do the graphical maths thing. Someone must want to prove me wrong, surely.
John Kaesehagen
Australia
Thank you so much for playing the game Tomasz, and bothering to check the calculations.
It can also be done with DC a meter or scope that shows True RMS when DC is present. [Check by reading a battery on the AC range.]
You can set up a sine wave that is offset by a DC value. You make a voltage waveform that is the same shape as the power waveform that we are talking about. Then you measure it.
There is a useful electronics website.
https://masteringelectronicsdesign.com/how-to-derive-the-rms-value-of-a-sine-wave-with-a-dc-offset/
On that page he shows the mathematics involved. Notice that a very simple formula right at the end/bottom covers what we are doing.
It gives an answer very close to yours too.
Regarding audio and perceived loudness: if you ever want to increase that impact of the sound without “cheating” by using a compressor, then just record to magnetic tape. You could even use a deck that has replay monitor heads immediately after the record heads so that it is close to real time.
To get up out of the noise they had to set up magnetic to work in a rather non-linear region. It automatically compressed. This was one of the things that made full digital audio sound different. They didn’t set out to compress “old” audio but it happened anyway.
That consistent loudness thing really annoys me too. Unfortunately some of the normalising programs cause other problems. Some of the problem is caused by people using the scope view in their digital software. When you have 20dB headroom it looks like you are working so far down that you must be in the noise. They also think that you are wasting that space. This is where metering methods become so important too. And some training/awareness.
Thanks to all the Nixie guys for tolerating this OT discussion too.
Regards,
John K
From: neoni...@googlegroups.com [mailto:neoni...@googlegroups.com] On Behalf Of Tomasz Kowalczyk
Sent: Thursday, 18 April 2019 04:04
To: neonixie-l
Subject: Re: [neonixie-l] OT: audio levels
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