Django built-in: cycle

[Mark Cuevas]

I'm using the following, which works, but doesn't break properly.  I'd like three across for each row.  How can I accomplish that?

{% for director in directors %}
  <tr class="{% cycle 'odd' 'even' %}">
      <td>
          {{ director.full_name }}
      </td>
  </tr>
{% endfor %}

[Mike Dewhirst]

On 6/06/2016 7:26 AM, Mark Cuevas wrote:
> I'm using the following, which works, but doesn't break properly. Â I'd
> like three across for each row. Â How can I accomplish that?

>
> {% for director in directors %}
> <tr class="{% cycle 'odd' 'even' %}">
> <td>
> {{ director.full_name }}
> </td>
> </tr>
> {% endfor %}

You need to pad out your list or queryset of directors so it comes to
mod(3) = 0

Use &nbsp; for the one or two extras

Then you can have three <td width="33%"> cells per row.

Mike


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[Mike Dewhirst]

On 6/06/2016 9:39 AM, Mike Dewhirst wrote:
> On 6/06/2016 7:26 AM, Mark Cuevas wrote:

>> I'm using the following, which works, but doesn't break properly. Â I'd
>> like three across for each row. Â How can I accomplish that?

>>
>> {% for director in directors %}
>> <tr class="{% cycle 'odd' 'even' %}">
>> <td>
>> {{ director.full_name }}
>> </td>
>> </tr>
>> {% endfor %}

But I forgot the "break properly"

<table>
<tr>
{% for item in synonyms.synonym_qs %}
<td width="33%">{{ item.name }}</td>
{% if forloop.last %}
</tr>
{% endif %}
{% if forloop.counter|divisibleby:3 %}
</tr><tr>
{% endif %}
{% endfor %}
</table>

You can see I made a synonyms class and populated it with a queryset.