How to get the Class name of my Suite?

[Gulshan Saini]

Hi,

I want to print out the suite class name and test class names in logs.
For test cases I achieved it by using  this.getClass().getSimpleName()
My test cases extends the suite class as shown below.

Issue: When i use this.getClass().getSimpleName() in my suite class it returns me class name of test case instead of suite name.

Output
[Parser] Running:
  F:\G_WorkSpace\Sel\testng.xml

Before Suite - TestCaseB
Executing Test Case TestCaseA
Executing Test Case TestCaseB
After Suite - TestCaseB

===============================================
Suite
Total tests run: 2, Failures: 0, Skips: 0
===============================================

Suite

import org.testng.annotations.AfterSuite;
import org.testng.annotations.BeforeSuite;


public class Suite {

    @BeforeSuite
    public void beforeSuite(){
        System.out.println("Before Suite - " + this.getClass().getSimpleName() );
    }
   
    @AfterSuite
    public void AfterSuite(){
        System.out.println("After Suite - " + this.getClass().getSimpleName());
    }
}


TestCaseA

import org.testng.annotations.Test;


public class TestCaseA extends Suite{

    @Test
    public void TestCaseA_01(){
        System.out.println("Executing Test Case " +  this.getClass().getSimpleName());
    }
   
}

TestCaseB
import org.testng.annotations.Test;


public class TestCaseB extends Suite{

    @Test
    public void TestCaseB_01(){
        System.out.println("Executing Test Case " +  this.getClass().getSimpleName());
    }
   
}

TestNG XML

<suite name="Suite">
  <test name="Suite Test Cases">
    <classes>
      <class name="TestCaseA"></class>
      <class name="TestCaseB"></class>
    </classes>
  </test>
</suite>

Please help.

Thanks
Gulshan

[Krishnan Mahadevan]

Implement a listener as below and hook up this listener to your test class and that should do.

public class MethodListener implements IInvokedMethodListener{

@Override

public void beforeInvocation(IInvokedMethod method, ITestResult testResult) {

}

@Override

public void afterInvocation(IInvokedMethod method, ITestResult testResult) {

BeforeSuite bs = method.getTestMethod().getConstructorOrMethod().getMethod().getAnnotation(BeforeSuite.class);

String msg ="";

if (bs != null){

msg = "Before Suite ";

}

AfterSuite as = method.getTestMethod().getConstructorOrMethod().getMethod().getAnnotation(AfterSuite.class);

if (as != null){

msg = "After Suite ";

}

if (!method.isTestMethod()){

msg += ":" +  method.getTestMethod().getConstructorOrMethod().getDeclaringClass().getCanonicalName();

System.out.println(msg);

}

}

}

Thanks & Regards
Krishnan Mahadevan

"All the desirable things in life are either illegal, expensive, fattening or in love with someone else!"

Gulshan

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[Gulshan Saini]

Thanks Krishnan for responding.

What is need of listener here? I just need to print out my Suite class name as I don't want to hardcode for each and every suite.
In logs it should show which suite is being executed.

Please try to put more light on your solution.

Thanks
Gulshan

[Krishnan Mahadevan]

I dont think I did any hard coding here Gulshan. All I did was to filter out the @BeforeSuite and @AfterSuite annotations from a global listener.

So you can very well add up this listener to your suite.xml file and work with it.

Thanks & Regards
Krishnan Mahadevan

"All the desirable things in life are either illegal, expensive, fattening or in love with someone else!"

Thanks
Gulshan

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[Gulshan Saini]

aahhh....You misunderstood me - I am not saying that you did any hardcoding. I was just telling that I dont wan't to hardcode the suite name.

I haven't worked with listeners so, I am not getting how to hook up listeners with my test cases.
My test cases are already extending the suite class.

Any help?

Thanks
Gulshan

[Gulshan Saini]

ooh it was simple

public class Suite {

    @BeforeSuite
    public void beforeSuite(){

        System.out.println("Before Suite - " + this.getClass().getSuperclass().getSimpleName());
       
    }
   
  
    @AfterSuite
    public void AfterSuite(){
        System.out.println("After Suite - " + this.getClass().getSuperclass().getSimpleName());
    }
}


rest if code remains same. What do you say, is the above approach correct?



Gulshan

[Krishnan Mahadevan]

Wouldnt work if there is multi level inheritance involved.

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Thanks & Regards
Krishnan Mahadevan

"All the desirable things in life are either illegal, expensive, fattening or in love with someone else!"

My Scribblings @ http://wakened-cognition.blogspot.com/

[Gulshan Saini]

Ya, I agree with u. So what should be approach?
Listeners are going top of my head

[Krishnan Mahadevan]

Gulshan
listeners arent that bad to figure out.
In your suite file you would plug in the listeners like below:

<listeners>

<listener class-name="com.example.MyListener" />

<listener class-name="com.example.MyMethodInterceptor" />

</listeners>

http://testng.org/doc/documentation-main.html#listeners-testng-xml

On Thursday, 26 January 2012, Gulshan Saini <gulsha...@gmail.com> wrote:
> Ya, I agree with u. So what should be approach?
> Listeners are going top of my head
>

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[Fakrudeen Shahul]

We can do this by using data from the stack trace. this will work fine even with multi level inheritance.

 

Code :

public

class Suite {

@BeforeSuite

public void beforeSuite(){

System.out.println("Before Suite - " + getClassName());

}

@AfterSuite

public void AfterSuite(){

System.out.println("After Suite - " + getClassName());

}

public String getClassName() {

final StackTraceElement[] ste = Thread.currentThread().getStackTrace();

return ste[2].toString().substring(0, ste[2].toString().indexOf("."));

}

}

Regards,

Fakrudeen