writing lambda

[smichr]

I'm trying to wrap an expression into a lambda and notice that the dummy variable of the lambda doesn't match with the variable of the expression. Am I doing this right?

Here, the lambda's i is not the same as the i in the expression I send:

>>> def f(fi):

...  return lambda i: fi

...

>>> f(i+1)(1)

i + 1

Here I remap the expression's i to the lambda's i

>>> def f(fi):

...  return lambda i: fi.subs(fi.free_symbols.pop(), i)

...

>>> f(i+1)(1)

2

/c

[krastano...@gmail.com]

The lambda has it's own local namespace. It searches in the global
namespace only if it does not find the variable in the local
namespace. As the dummy variable is introduced it creates the key 'i'
in the local dictionary, so you can be sure that it won't touch upon
any 'i's in the global.

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