Time to spin the kooks up again. Melt, kooks, melt. <snicker>
James McGinn, in
<
news:a232469e-70e7-4b66...@googlegroups.com> did
thusly jump head first into the wood chipper again:
> On Sunday, March 13, 2016 at 10:42:37 PM UTC-7,
> Friendly Neighborhood Vote Wrangler Emeritus wrote:
>>> Unless you know that application of Avogadro's law will give you nonsense results, and you will have no way of knowing.
>> Except it doesn't give "nonsense results", Jim. You're just a kooktard
>> desperately backpedaling because I've used scientific fact to utterly
>> destroy your kooky conspiracy theory. You have no refutation of that
>> scientific fact.
>>
>> Why can't you grasp reality, Jim?
> LOL.
Your insane laughter is no substitute for refutation of the scientific
data which proves your kooky claims are nothing more than the mad
ranting of a thoroughly insane kooktard, James. You lose. Again.
==========================================================
Still demonstrating your inability to grasp how water can be gaseous
phase below its boiling point, James? It's already been fully
explained to you, and in the process, your kooky conspiracy theory has
been utterly demolished.
You postulate the following:
1) There is a "plasma not-a-plasma" that exists in the troposphere,
which you have admitted is merely a hypothetical construct so you can
continue to blather on about your kooky discredited conspiracy theory.
2) This magical "plasma not-a-plasma" is plasmized by an energy source
that is somehow magically plasmizing water in the troposphere without
dissociating it, given that the dissociation energy and nuclear
binding energy of water are identical at 940.8 kJ/mol, and thus water
will dissociate rather than plasmize, unless hit with an extremely
energetic laser.
3) That your kooky energy source is somehow plasmizing only
atmospheric water while not plasmizing or dissociating Earth-bound
water, and is not killing off all life on the planet. Given that the
*minimum* energy necessary to even *begin* to plasmize water would be
equivalent to photons at a *maximum* wavelength of 103.32 nm, just
3.32 nm away from the x-ray range, I'm sure even you can see the
problem inherent in your contention, James.
4) That this magical energy source exists in the troposphere. Except
it cannot exist in the troposphere. Photons of shorter wavelength than
~121 nm are absorbed far above the troposphere due to their ability to
ionize air, thus they are not present in the troposphere, where the
overwhelming majority of all water is.
5) That warm air is heavier than cooler air... tell me, Jim... which
direction does air flow from a flame? Oh, that's right, upward. Why?
Because warm air is lighter and less dense than cooler air and thus
convects upward.
6) That air with gaseous phase water in it is heavier than dry air,
except you forget that science has long known about molar mass and
molar volume...
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////////////////////////////////////////////////////////////
Air temperature is a much greater determiner of air density than
humidity.
The molar mass of water is 18.02 g/mol, as calculated from the sum of
the atomic masses of its constituent atoms.
The average molar mass of air (approximately 78% nitrogen, 21% oxygen,
1% other gases) is 28.57 g/mol at STP.
Thus using Avogadro's Law and the Ideal Gas Law, water in its gaseous
phase and air have a molar volume of 22.414 L/mol at STP. IOW, a molar
mass of air and a molar mass of water in its gaseous phase occupy the
same volume of 22.414 liters at STP.
The density of water in its gaseous phase at STP is 0.804 g/L, whereas
the density of dry air is 1.27 g/L at STP.
Therefore that 22.414 liters molar volume would weigh:
18.02 grams for water in its gaseous phase
28.57 g for dry air
Therefore, water in its gaseous phase is lighter than air. Therefore
air containing water in its gaseous phase is lighter than dry air.
Therefore, drier air *must* sink through air laden with water in its
gaseous phase, because it is less buoyant.
Except that's not all, Jim. Because air becomes denser as the altitude
decreases.
At any given altitude, air of the same temperature and gaseous water
partial pressure will have the same density.
At any given altitude, air of lower temperature but similar gaseous
water partial pressure will have higher density.
At any given altitude, air of the same temperature but greater gaseous
water partial pressure will have lower density.
For air of the same temperature and gaseous water partial pressure,
air at a higher altitude will have lower density.
(1) For instance, at sea level, 20 C temperature, and 0% relative
humidity, the air density is 1.204 kg/m^3.
Keeping all other factors in (1) the same but increasing relative
humidity to 100%, or elevation to 74 meters, or temperature to 22.4 C,
the air density is 1.194 kg/m^3.
Thus in order for the air at sea level to rise 74 meters due to
increased buoyancy, it must have 100% more relative humidity than the
air 74 meters above (IOW, the air at sea level must be at 100% RH, the
air 74 meters above must be at 0% RH), given the same temperature; or
the temperature of that sea level air must be at least 2.4 C greater
than the air at 74 meters, given the same relative humidity.
Given that temperature can change much more than 2.4 C, whereas
relative humidity can only max out at 100%, one can see that
temperature-induced convection is the predominant driver of weather
systems, destroying yet another of your kooky contentions.
IOW, in order for air to rise, it must overcome gravity, which
requires energy (said energy in the form of temperature of the air
itself decreasing air density or the latent heat of vaporization of
monomer water in its gaseous phase replacing a certain percentage of
higher molar weight air molecules and thus decreasing air density).
It's not because of your blather that the air at a lower altitude is
"heavier" due to "water droplets", Ko0okTard.
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And before you begin blathering on again about the Ideal Gas Law not
applying to the atmosphere, let me remind you that I've done the
calculations for the van der Waals equation, as well. It is in
agreement with the Ideal Gas Law to a great degree of accuracy even
with the molar volume I used. As air volume increases for the same
relative humidity, air with gaseous phase water in it acts more and
more like an ideal gas, Jim. Compare the Ideal Gas Law to the van der
Waals Equation with all parameters the same except for volume, and
increase the volume through several iterations, then plot the
difference between the results of the Ideal Gas Law and the van der
Waals equation... notice the converging trend?
Do you think for an Earth-atmosphere-sized container, the air with
gaseous phase water in it would be within a very small margin of error
to an ideal gas, Jim? Sure it is. But that's something else you don't
understand because you're a low-information uneducated oaf.
7) Your kooky contention that water polarity changes upon H bonding...
which would also cause random changes in water's solvent properties,
and we know water's solvent properties do not change randomly, Jim.
You didn't know about the two spin isomers of water, which means there
are two hybrids of water with different H bonding strengths:
<
https://youtu.be/7hGqlEpvODw?t=2156>
They used x-ray spectroscopy to determine photon energy from electron
orbital shell descent. You'll note the gaseous phase water molecule's
photon spectra peaks at a much lower photon energy than ice. This is
due to differences in hydrogen bonding strength between the two
phases.
<
https://youtu.be/7hGqlEpvODw?t=2304>
You'll note the double peak of liquid water.
Professor Anders Nilsson, SLAC National Accelerator Laboratory:
====================================================
Two peaks, what does that mean? Could it be two different types of
water molecules then, in the liquid? And if you look at it, one of the
peaks is very close to the gas phase and the other peak is closer to
the ice. So it looks like water contains two types of molecules.
====================================================
You betcha... para and ortho-form water.
<
http://www1.lsbu.ac.uk/water/ortho_para_water.html>
====================================================
Each hydrogen atom in water has a magnetic moment, which is associated
with the proton's spin of 1/2. As is found in molecular hydrogen (H2),
the protons (within the hydrogen atoms) in water (H2O) may possess
parallel or antiparallel nuclear spin (see right). When the spins are
parallel, there is a paramagnetic state called ortho-H2O with a
magnetic moment = 1. This is the high spin (triplet) state with three
symmetric spin states +1 , 0 , -1 (^^, ^v+^v, vv) where the three
states have equal energy in a zero magnetic field. This spin state
always possesses positive energy with a minimum energy level of 284.7
J mol-1 (23.794352 cm-1) H216O, [607c], 284.4 J mol-1 (23.773510 cm-1)
H217O [607a] or 284.2 J mol-1 (23.754902 cm-1) H218O [607a].
When the spins are opposed there exists the nonmagnetic state called
para-H2O with magnetic moment = 0 with just one antisymmetric spin
state (^v-^v) and magnetic moment = 0. Some of the water molecules in
this low spin (singlet) state will not be rotating even at room
temperature.
Para-H2O does not interact with an external magnetic field, but
ortho-H2O does. Conversion between these isomers is symmetry forbidden
for isolated water molecules and they act as different molecular
species. They can change spin state on interaction with another
particle, including other water molecules. The equilibrium ratio of
these nuclear spin states in H2O is all para- at zero Kelvin, where
the molecules have no rotational spin in their ground state, shifting
to the most stable ratio [1694] of 3:1 ortho:para, in the relative
amounts of the number of magnetic states, at less cold temperatures
(>50 K, see left [2478]); the equilibrium taking months to establish
itself in ice (or gas) and nearly an hour in ambient water [410]. It
is now thought that the ratio lies far from equilibrium and much
closer to 1:1 in liquid water due to hydrogen bond formation [2076].
This means that liquid H2O effectively consists of a mixture of
non-identical molecules and the properties of pure liquid ortho-H2O or
para-H2O are unknown. The differences in the properties of these two
forms of water are expected to be greater in an electric field [1186],
which may be imposed externally, from surfaces or from water
clustering itself. Many materials preferentially adsorb para-H2O due
to its non-rotation ground state [410, 835].
The apparent difference in energy between the two states is a
significant 1-2 kJ mol-1, far greater than expected from spin-spin
interactions (< μJ mol-1) [835]. It has been suggested that structural
rearrangements may be induced by ortho-H2O : para-H2O conversion
[1430], as it is possible that hydrogen bonds between para-H2O,
possessing no ground state spin, are stronger and last longer than
hydrogen bonds between ortho-H2O [1150]. It is thus possible that
ortho-H2O and para-H2O form separate hydrogen bonded clusters [1150]
with para-H2O being preferred in the low density tetrahedrally
coordinated clusters and ortho-H2O being preferred in the high density
clusters [2070], where their rotation is more easily accommodated.
Picoliter samples of pure ortho-H2O and para-H2O may be separated in a
strong dc electric field [2156].
====================================================
The two spin isomers of water cause a different H bond strength when
water molecules of like spin isomers engage in H bonding to form water
clusters, Jim. Thus the weaker ortho-H2O hydrogen bond is more easily
broken, so most of the gaseous phase water being evaporated should be
ortho-H2O. You'll note above that ortho-H2O even in its liquid form is
very close to the same properties as gaseous phase water under x-ray
spectroscopy, the difference accountable by taking into consideration
temperature and phase.
Remember when I said the surface layer of water was more viscous than
the bulk water? Yeah, that's because the ortho-H2O being evaporated
removes heat from the water, which makes the para-H2O in the ~1.7 nm
thick surface layer act nearly the same as ice.
<
http://www1.lsbu.ac.uk/water/interfacial_water.html>
=====================================================
Analysis of simple thermodynamics c shows the surface has considerable
structuring, having identical density to that of bulk water at just
under 4 °C. In addition, the surface water structuring varies less
with temperature than the bulk. Refractive index study of the
water-air surface reveals it to be about 1.7 nm thick at 22 °C and
more dense than the bulk liquid (that is, it behaves like water at a
lower temperature).
=====================================================
As for condensation? Well, it's been found that under circumstances in
which relative humidity is less than ~25%, a four-molecule thick layer
of ice forms on the condensation surface... so apparently what is
happening is that the ortho-H2O being evaporated is colliding with
other molecules in the air, changing their spin isomer and thus giving
off energy, becoming para-H2O, and those are the ones preferentially
condensing, forming that four-molecule thick layer of ice. You'll note
above that para-H2O even in its liquid form is very close to the same
properties as solid phase water (ice) under x-ray spectroscopy, the
difference accountable by taking into consideration temperature and
phase.
For conditions of greater than ~25% relative humidity and thus greater
water gaseous-phase partial pressure in the air, apparently the
condensation process is fast enough to allow even ortho-H2O
gaseous-phase water to condense, thus the four-molecule thick layer of
ice is melted.
So you see, James, it's not because of your kooky contention that the
water molecule's polarity changes upon hydrogen bonding, it's because
there are two spin-isomer hybrids of the water molecule with two
different hydrogen bonding strengths.
Yet again, your kooky conspiracy theory is ripped to shreds by
scientific fact... made especially delicious because it was done
utilizing a link *you* provided. LOL
<
http://phys.org/news/2014-09-para-ortho.html>
==============================================
A hydrogen nucleus (proton) can adopt two different states, comparable
to rotation clockwise and counterclockwise. In the case of water, the
nuclear spins of the two — indistinguishable — protons can be combined
in four different ways: one antisymmetric and three symmetric
wavefunctions. Water adopting the antisymmetric wavefunction is called
para water, whereas water adopting one of the symmetric ones is called
ortho water. Because switching from one state to the other is
"forbidden" due to quantum-mechanical symmetry rules, the two spin
isomers cannot interconvert without external influences such as
collisions.
==============================================
Were you not aware that hydrogen has two spin isomers, ortho- and
para-, and thus water, comprised of one oxygen atom and two hydrogen
atoms, also has two spin isomers?
<
https://qph.is.quoracdn.net/main-qimg-f24e171918d462fac89b809dccaa7c3e>
<
http://cdn.phys.org/newman/csz/news/800/2014/201434press.gif>
In pure hydrogen, ortho-hydrogen is thermodynamically unstable even at
low temperature and / or high pressure and it thus spontaneously
converts to para-hydrogen upon molecular collision, which has
implications for liquefied hydrogen storage, as energy is given off by
this spin isomer conversion.
In water, the oxygen atom slows the already slow conversion process to
para-hydrogen by preserving spin state of the hydrogen atom via
partially shielding the hydrogen atom from molecular collision which
would cause spin isomer conversion.