Whats the point of having dicts in templates if one cannot access them by key?

[Juan Pablo Tamayo]

Let me explain, I have a nested dictionary like:

agenda = {'3': {'2012-11-11': <MyObject>, '2012-11-14': <MyObject>, ...},

  '7': {'2012-11-9': <MyObject>, },

  '2': {'2012-10-28': <MyObject>},

  }

And I want to access it by specifying the two keys. I've red that i must access the dict like (where attribute is an attribute of <MyObject>:

{% for k, a_dict in agenda.items %}

  {{ k }}

  {% for k2, v in a_dict.items %}

    {{ k }}-{{ k2 }}-{{ v.attribute }}

  {% endfor %}

{% endfor %}

But, whats the point of using dicts if I have to access the values in whatever order the <Dict>.items() gives me the keys and values?

What if I need to access these values in a specified order? (for the outer dict AND the inner ones)

Is there a way to access a two-dimensional container IN AN PRE-SPECIFIED ORDER?

Thaks for any advise.

pablete

[Lachlan Musicman]

I used the SortedDict datastructure :)

https://docs.djangoproject.com/en/dev/ref/utils
or
/path/django-docs/ref/utils.html#django.utils.datastructures.SortedDict

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[Bill Freeman]

I believe that if the keys were valid python identifiers you could access them using dot notation.  E.g.; if a_dict is dict(a=dict(aa='foo')), then in the template you could say {{ a_dict.a.aa }}.  This may work with the simple numbers, but with the keys containing minuses there may be problems.  You could try quoting them.

If none of that stuff is going to work for you, you aught to be able to write a simple template filter that filters the dict, and takes the key as a quoted fight hand argument.  You then cascade this for nested dictionaries.

But if it were me, I'd probably see if I couldn't do it in the view, producing lists or tuples with the stuff in the order you need them.

Bill

[Juan Pablo Tamayo]

Thank you all. I have fix my issue icons sorteddict from the Python collections.

Juan Pablo Tamayo H
Sent from my Android phone

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