To do the calculation you desire, we'd need to know the length of the
amplicon (what you're trying to PCR).
You can estimate grams out using the average mass of a nucleotide, and
assuming your PCR reaction goes until completion (you use all the
primers). You can do it based on number of cycles and starting DNA
present, but this way is much easier.
If you go until completion, you can assume your 0.2 micromoles of
primer have simply turned into 0.1 or 0.2 micromoles of full-length
amplicon (depending on if the 0.2 micromoles was one only or both of
your primers total). The important part is that since 2 moles of
primer go to 1 mole of amplicon, that you do the math right. (Left
primer and Right primer join in the middle, going from 2 molecules to
1 molecule).
So if I assume you added 0.2 micromoles of Forward primer and the
amplicon is 500bp long, at completion there will be 0.2 micromoles of
amplicon. A quick googling shows the average for dsDNA "1 pmol of 1000
bp DNA = 0,66 µg" so:
(.66uG / 1000bp) * picomoles_per_micromole * micromoles_present * base_pairs
(.66/1000) * 1000000 * .2 * 500 = 66000 micrograms
if it was done in 50uL reaction, that's 1320 uG/uL
Again, this is assuming the PCR goes to completion (no remaining
primer) and no mispriming happens (this will contribute to the final
mass, but it's noise and you won't know exactly what the length is) or
polymerase falling off and not completing an amplicon completely (this
is why you generally have the last PCR cycle much longer, to allow it
to play catch-up)
--
-Nathan