The canonical example of an associative, non-commutative operator is
matrix multiplication, but for the life of me I can't think of the
other kind.
My imagination tells me something to do with unordered binary trees,
but I can't think of a domain where that naturally fits.
Mitch
Look up "Jordan algebras."
--
Tim Chow tchow-at-alum-dot-mit-dot-edu
The range of our projectiles---even ... the artillery---however great, will
never exceed four of those miles of which as many thousand separate us from
the center of the earth. ---Galileo, Dialogues Concerning Two New Sciences
www.ams.org/bull/1997-34-02/S0273-0979-97-00712-X/S0273-0979-97-00712-X.pdf
H
A special case of Jordan algebras are Lie algebras in
characteristic 2. They might be more familiar. In
general, for an associative algebra, the operation
that takes two elements x and y and returns xy+yx
is a Jordan algebra, but there are other exceptional
Jordan algebras as well.
> Is there a 'natural' example of a commutative, non-associative
> operator?
I'm not sure about 'natural', but here are some examples.
Let # denote a binary operation, whose specific definition
(including domain, which should be clear so I'll omit it)
will vary in what follows. Both [1] and [2] give the example
a#b = (a+b)/2. Item [2] goes on to give the examples
a#b = sqrt(ab), a#b = (ab)^(-1), a#b = |a - b|, and
min{a&b, b&a} where & is the operation of catenation for
positive integers written in decmial form (so 349&28 is 34,928).
Finally, [3] gives 3 examples of a binary operation on a set
each of which satisfies all the axioms of a commutative group
except associativity.
[1] Editorial Staff, "Another binary operation -- and a challenge",
Mathematics Student Journal 15 #4 (May 1968), 6.
[2] Nitsa Movshovitz-Hadar and Rina Hadass, "Between associativity
and commutativity", International Journal of Mathematical
Education in Science and Technology 12 #5 (1981), 535-539.
[3] Louis O. Kattsoff, "The independence of the associative law",
American Mathematical Monthly 65 #8 (October 1958), 620-622.
Dave L. Renfro