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Antilog

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Jerry Martin

no leída,
8 ene 2003, 11:06:21 p.m.8/1/2003
para

Can any one out there tell me if it is possible find the
antilog when using spreadsheets ?

Norman Harker

no leída,
9 ene 2003, 1:14:51 a.m.9/1/2003
para
Hi Jerry!

You might imagine that this is a common question.

Here's a response by Chip Pearson I found using Google Search on Antilog

The LOG function returns a base-10 logarithm. Therefore, the inverse
function
is simply raising the 10 to that power. E.g.,

=10^B1

If you are using the LOG function to get the log in an arbitrary base, such
as

=LOG(A1,B1)
raise the base in B1 to the LOG result. E.g.,
=B1^C1

If you are using the LN function to get the base-e log, use EXP to do the
inverse. E.g.,

=EXP(B2)

See:

http://groups.google.com/groups?hl=en&lr=&ie=UTF-8&selm=e9syyEk3BHA.2524%40tkmsftngp07

For Google Searching:

Try Ron de Bruin's Add-In from:

http://www.rondebruin.nl/Google.htm

This puts a Google search tool under Help and provides help where yo want it
when you want it.

Or you can use:

you can find all postings on google

http://groups.google.com/advanced_group_search?q=group:*Excel*

This searches Excel postings generally

--
Norman Harker
Sydney, Australia.
njha...@optusnet.com.au

"Jerry Martin" <jerb...@comcast.net> wrote in message
news:1ca401c2b794$77d84460$d4f82ecf@TK2MSFTNGXA11...

ekta...@gmail.com

no leída,
3 dic 2012, 8:43:26 a.m.3/12/2012
para
Thanx

plinius

no leída,
3 dic 2012, 9:24:01 a.m.3/12/2012
para
=LN(123456) = 11.7236401
=EXP(11.7236401) = 123456

=LOG(123456) = 5.091512202
=10^5.091512202 = 123456

=LOG(123456,16) = 4.228409357
=16^4.228409357 = 123456


Hi,
E.

julien....@gmail.com

no leída,
24 may 2019, 9:55:59 p.m.24/5/2019
para
Mate thank you so much, that makes perfect sense and you have helped a lot with my assignment!
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