sum numbers is a column

[VilMarci]

Dear Group,

I have a big issue.
Here's the situation:
I have numbers in a column:

123
465
782
134
...
lot of numbers....

And a few sums: 1313, 6464...

I have to find out where those sums are coming from. They should be sums of
the numbers in that column.
To make things harder I do not know how many numbers shall I add together.

Please advise how to write a fuction that helps me out. I know vba but this
looks a bit over my skills.

Many thanks,
Marton

[Tom Ogilvy]

Sub AAA()
Dim rng As Range, cell As Range
Set rng = Columns(1).SpecialCells(xlFormulas, xlNumbers)
For Each cell In rng
MsgBox cell.Address & vbNewLine & _
cell.Formula & vbNewLine & _
cell.DirectPrecedents.Address
Next

End Sub

this probably isn't what you want, but it may give you some ideas.

--
Regards,
Tom Ogilvy

"VilMarci" wrote:

> Dear Group,
>
> I have a big issue.
> Here's the situation:
> I have numbers in a column:
>
> 123
> 465
> 782
> 134

> ....

[tony h]

if the sums are formulae have you tried the auditing tools
(tools...auditing). Select the cell with the formula and then "show
precedants"

or have I misunderstood the question?

--
tony h
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View this thread: http://www.excelforum.com/showthread.php?threadid=529570

[Niek Otten]

Hi Marton,

If you mean find the numbers that add up to the sum: you can find many discussions in the Google archives, and lots of warnings
about how this will "eat" your computer.
But the following code from Harlan Grove is said to be the best. Maybe you should try with small sets first.

--
Kind regards,

Niek Otten

'Begin VBA Code

' By Harlan Grove

Sub findsums()
'This *REQUIRES* VBAProject references to
'Microsoft Scripting Runtime
'Microsoft VBScript Regular Expressions 1.0 or higher

Const TOL As Double = 0.000001 'modify as needed
Dim c As Variant

Dim j As Long, k As Long, n As Long, p As Boolean
Dim s As String, t As Double, u As Double
Dim v As Variant, x As Variant, y As Variant
Dim dc1 As New Dictionary, dc2 As New Dictionary
Dim dcn As Dictionary, dco As Dictionary
Dim re As New RegExp

re.Global = True
re.IgnoreCase = True

On Error Resume Next

Set x = Application.InputBox( _
Prompt:="Enter range of values:", _
Title:="findsums", _
Default:="", _
Type:=8 _
)

If x Is Nothing Then
Err.Clear
Exit Sub
End If

y = Application.InputBox( _
Prompt:="Enter target value:", _
Title:="findsums", _
Default:="", _
Type:=1 _
)

If VarType(y) = vbBoolean Then
Exit Sub
Else
t = y
End If

On Error GoTo 0

Set dco = dc1
Set dcn = dc2

Call recsoln

For Each y In x.Value2
If VarType(y) = vbDouble Then
If Abs(t - y) < TOL Then
recsoln "+" & Format(y)

ElseIf dco.Exists(y) Then
dco(y) = dco(y) + 1

ElseIf y < t - TOL Then
dco.Add Key:=y, Item:=1

c = CDec(c + 1)
Application.StatusBar = "[1] " & Format(c)

End If

End If
Next y

n = dco.Count

ReDim v(1 To n, 1 To 3)

For k = 1 To n
v(k, 1) = dco.Keys(k - 1)
v(k, 2) = dco.Items(k - 1)
Next k

qsortd v, 1, n

For k = n To 1 Step -1
v(k, 3) = v(k, 1) * v(k, 2) + v(IIf(k = n, n, k + 1), 3)
If v(k, 3) > t Then dcn.Add Key:="+" & _
Format(v(k, 1)), Item:=v(k, 1)
Next k

On Error GoTo CleanUp
Application.EnableEvents = False
Application.Calculation = xlCalculationManual

For k = 2 To n
dco.RemoveAll
swapo dco, dcn

For Each y In dco.Keys
p = False

For j = 1 To n
If v(j, 3) < t - dco(y) - TOL Then Exit For
x = v(j, 1)
s = "+" & Format(x)
If Right(y, Len(s)) = s Then p = True
If p Then
re.Pattern = "\" & s & "(?=(\+|$))"
If re.Execute(y).Count < v(j, 2) Then
u = dco(y) + x
If Abs(t - u) < TOL Then
recsoln y & s
ElseIf u < t - TOL Then
dcn.Add Key:=y & s, Item:=u
c = CDec(c + 1)
Application.StatusBar = "[" & Format(k) & "] " & _
Format(c)
End If
End If
End If
Next j
Next y

If dcn.Count = 0 Then Exit For
Next k

If (recsoln() = 0) Then _
MsgBox Prompt:="all combinations exhausted", _
Title:="No Solution"

CleanUp:
Application.EnableEvents = True
Application.Calculation = xlCalculationAutomatic
Application.StatusBar = False

End Sub

Private Function recsoln(Optional s As String)
Const OUTPUTWSN As String = "findsums solutions" 'modify to taste

Static r As Range
Dim ws As Worksheet

If s = "" And r Is Nothing Then
On Error Resume Next
Set ws = ActiveWorkbook.Worksheets(OUTPUTWSN)
If ws Is Nothing Then
Err.Clear
Application.ScreenUpdating = False
Set ws = ActiveSheet
Set r = Worksheets.Add.Range("A1")
r.Parent.Name = OUTPUTWSN
ws.Activate
Application.ScreenUpdating = False
Else
ws.Cells.Clear
Set r = ws.Range("A1")
End If
recsoln = 0
ElseIf s = "" Then
recsoln = r.Row - 1
Set r = Nothing
Else
r.Value = s
Set r = r.Offset(1, 0)
recsoln = r.Row - 1
End If
End Function

Private Sub qsortd(v As Variant, lft As Long, rgt As Long)
'ad hoc quicksort subroutine
'translated from Aho, Weinberger & Kernighan,
'"The Awk Programming Language", page 161

Dim j As Long, pvt As Long

If (lft >= rgt) Then Exit Sub
swap2 v, lft, lft + Int((rgt - lft + 1) * Rnd)
pvt = lft
For j = lft + 1 To rgt
If v(j, 1) > v(lft, 1) Then
pvt = pvt + 1
swap2 v, pvt, j
End If
Next j

swap2 v, lft, pvt

qsortd v, lft, pvt - 1
qsortd v, pvt + 1, rgt
End Sub

Private Sub swap2(v As Variant, i As Long, j As Long)
'modified version of the swap procedure from
'translated from Aho, Weinberger & Kernighan,
'"The Awk Programming Language", page 161

Dim t As Variant, k As Long

For k = LBound(v, 2) To UBound(v, 2)
t = v(i, k)
v(i, k) = v(j, k)
v(j, k) = t
Next k
End Sub

Private Sub swapo(a As Object, b As Object)
Dim t As Object

Set t = a
Set a = b
Set b = t
End Sub
'---- end VBA code ----

"VilMarci" <dont...@here.mail> wrote in message news:OsmK2v9V...@TK2MSFTNGP14.phx.gbl...

[VilMarci]

Hallo Niek,

Thanks for the code.
This is working perfectly :)

Marton

"Niek Otten" <nico...@xs4all.nl> wrote in message
news:u0H66C%23VGH...@TK2MSFTNGP15.phx.gbl...

[VilMarci]

Hello,

Just 1 more thing...
How would possible to include negative numbers?

Marton

"Niek Otten" <nico...@xs4all.nl> wrote in message
news:u0H66C%23VGH...@TK2MSFTNGP15.phx.gbl...

[Niek Otten]

Hi Marton,,

No idea, really. I thought it worked OK, but a quick test learned me that seems not to be the case.
Sorry I can't help you any further.

You could try Google's newsgroup archives and search for: combinations, sum, harlan, dana
and find out more

--
Kind regards,

Niek Otten

"VilMarci" <dont...@here.mail> wrote in message news:uat0NJKW...@TK2MSFTNGP05.phx.gbl...

[Niek Otten]

Couldn't you adjust the base? Like add lowest number+1 to all numbers and the search argument and subtract again from the results?

--
Kind regards,

Niek Otten

"VilMarci" <dont...@here.mail> wrote in message news:uat0NJKW...@TK2MSFTNGP05.phx.gbl...

[Niek Otten]

No, not like that. But somehow it should be possible to work with a different base (?)

--
Kind regards,

Niek Otten

"Niek Otten" <nico...@xs4all.nl> wrote in message news:eePwC8XW...@TK2MSFTNGP05.phx.gbl...

[Niek Otten]

Hi Marton,

If you follow this link there is a routine by Ioannis who claims (somewhere in the supporting discussions) it does negative
numbers as well. I didn't test it.

--
Kind regards,

Niek Otten

"VilMarci" <dont...@here.mail> wrote in message news:uat0NJKW...@TK2MSFTNGP05.phx.gbl...

[Niek Otten]

Sorry:

http://www.mrexcel.com/pc09.shtml

--
Kind regards,

Niek Otten

"Niek Otten" <nico...@xs4all.nl> wrote in message news:OGlnirjW...@TK2MSFTNGP05.phx.gbl...