find a .py path

[hg]

Hi,

Is there an easy way for a script being executed (from anywhere) to know
where is is ... something in os.path ?

Thanks,

hg

[hg]

hg wrote:

oops: os.path.abspath(sys.argv[0])

hg

[Laszlo Nagy]

hg i'rta:

> Hi,
>
> Is there an easy way for a script being executed (from anywhere) to know
> where is is ... something in os.path ?
>

__file__

You can also use os.argv[0] but that is not the same...

Laszlo

[hg]

Laszlo Nagy wrote:

Thanks

[Laszlo Nagy]

hg írta:

Be aware with this. It is different when you do

/usr/bin/python prog.py

and

./prog.py

In the first case, sys.argv[0] will be /usr/bin/python!

You should better use

os.path.abspath(__file__)

(that will work for normal python programs, but not for py2exe compiled
programs or for modules imported from a zip file...)

Best,

Laszlo

[laurent rahuel]

Hi,

What about :

import os.path
print os.path.abspath(__file__)

hg a écrit :

[Gabriel Genellina]

On 5 ene, 13:33, Laszlo Nagy <gand...@designaproduct.biz> wrote:

> Be aware with this. It is different when you do
>
> /usr/bin/python prog.py
>
> and
>
> ./prog.py
>
> In the first case, sys.argv[0] will be /usr/bin/python!

No, sys.argv[0] is always the running script, and sys.argv[1] the first
argument after the script, and so on. It doesn't matter if you call
python implicitely, or with other options. Try this:
/usr/bin/python -i -u -O prog.py

--
Gabriel Genellina