calculate the power and the total cost of generation using lambda iteration method,considering generator limits and inluding transmission losses

[Mohamed Khairi Rafeek]

Power demand 120MW

[Johan Löfberg]

42mV

[Mohamed Khairi Rafeek]

what 42mV?

[Johan Löfberg]

A consistent answer to the question "120MW"

[Johan Löfberg]

and your question appears off-topic as I don't see any YALMIP code here

[Mohamed Khairi Rafeek]

i've attached the m-file..

[Mohamed Khairi Rafeek]

A=[200 180 140];
B=[7 6.3 6.8];
G=[0.008 0.009 0.007];
BL=[0.000218 0.000093 0.000028
    0.000093 0.000228 0.000017
    0.000028 0.000017 0.000179];
Pd=170;
Ng=3;
lambda=7;
dp=10;
dlambda=.01;
Pmin=[10 10 10];
Pmax=[85 80 70];
P=[0 0 0];
while abs(dp) >= .001
    SS=2*BL*P';
        for i=1:Ng;
        for j=1:Ng;
            S(i) = SS(i)-(2*BL(i,j)*P(i));
            P(i)=(lambda*(1-S(i)))-B(i)/2*(G(i)+lambda*BL(i,i));
            if P(i)>Pmax(i)
                P(i)=Pmax(i);
            elseif P(i)<Pmin(i)
                    P(i)=Pmin(i);
                end
        end
        end
    pt=sum(P);
    PL=P(i)*BL(i,j)*P(j);
    for i=Ng;
    dp=P(i)-PL-Pd;
    end
  
    if dp>0
        lambda=lambda-dlambda;
    elseif dp<0
        lambda=lambda+dlambda;
    end
end
Pd
P
lambda
Total_Cost=sum(A+B.*P+G.*P.^2)

[Johan Löfberg]

You still haven't asked any question, or told us what this has to do with yalmip