I can not define "constraint". Is this the compatibility problem?

[Yu Yang]

Hi,

 

    I am forced to use the MATLAB 2013b(64bit) by the university, so I don't know if my problem is due to the compatibility.

 

    When I follow the instruction part to define the constraint:

 

     x_premium=sdpvar(10,1)
    

     Constraint=[x_premium>=0]

 

   an error information comes out:

    Error using table (line 281)
    Wrong number of arguments.

 

    Error in lmi/display (line 120)
    table('',headers,data)

    Error in constraint/display (line 3)
    display(set(X));

    Caused by:
      You may have intended to create a table with one row from one or more variables that are character strings.
      Consider using cell arrays of strings rather than character arrays. Alternatively, create a cell array with one
      row, and convert that to a table using CELL2TABLE.

 

    I would really appreciate if anybody can figure it out and help me to solve this simple problem!  Many thanks.

 

Regards,

 

Yu  

 

[Johan Löfberg]

See here

https://groups.google.com/forum/?fromgroups#!topic/yalmip/WwuKJj6Tmwc

Simply put a ; after your constraint definitions so that the display code isn't run (only yalmiptest, display and checkset are affected by this bug)

or wait for a patched version (hopefully I remember to release it today)

[Johan Löfberg]

New release fixes this issue.

[Yu Yang]

Dear Johan,

 

    Thanks a lot! 

   

    I have tested it. Everything goes well now!  I have the greatest respect to your work and your kind help to the entire research community.

 

Best regards,

 

Yu