Short answer: the antisymmetry is in indices 1 and 3. That's a convention choice in xAct. But it is not explicit...
Longer answer: Let us discuss conventions, and I'm going to use xAct terminology, using the opportunity to explain other things:
Christoffel tensors (i.e. differences of connections) have three indices: there are two indices on the same vector bundle, one up and one down, and then there is a third index (which I'll call the "differentiation index") in the tangent bundle, another down index. The first two indices do not need to be in the tangent bundle, but the differentiation index is always on the tangent bundle. (xAct uses AChristoffel instead of Christoffel for the case when the vector bundle of those two indices is not the tangent bundle, but we don't need this here.) Different authors use different orders for these three indices. The convention in xAct is Christoffel[up, diffdown, down], where the up, down indices are the first two indices above and the diffdown is the differentiation index. The symmetries of this Christoffel tensor depend on where this tensor comes from.
If this Christoffel is the difference between the Levi-Civita connection of a metric and an ordinary derivative (both on the tangent bundle), which is the standard situation in GR, then the Christoffel has the usual symmetry in the indices 2 and 3.
The situation we are discussing here is different: we have a metric g and its Levi-Civita cd. Then we have a frame B (your fred) in which the metric has constant components (not necessarily 0, 1, or -1). This frame B has a parallel derivative (called PDB in xAct/xCoba) which has torsion in general (hence it is not an ordinary derivative). The "Ricci rotation coefficients" are just the Christoffel tensor between cd and PDB, and again has indices Christoffel[up, diffdown, down], though it is usually presented lowering the first index with the metric, so that we have Christoffel[down, diffdown, down]. This tensor is now antisymmetric in the first and third indices in the conventions of xAct.
In your notes, the two up-down indices a, b appear in positions 2 and 3. The differentiation index mu appears in position 1. So we see how conventions differ. The partial has the differentiation index mu, of course.
Let me show it with xAct. First we need to define the manifold, the general basis (i.e. not-coordinated) and the metric:
<< xAct`xCoba`
DefManifold[M, 4, {a, b, c, d, e, f}]
DefBasis[B, TangentM, {0, 1, 2, 3}]
DefMetric[-1, g[-a, -b], cd]
Define the Ricci rotation tensor. This is just Christoffel[cd, PDB] as I said above, which is internally called ChristoffelcdPDB. I want to show that this object is antisymmetric in the first and third indices. Symmetrize them, then convert to derivatives of the metric and canonicalize:
In[]:= Christoffel[cd, PDB][-a, -b, -c] + Christoffel[cd, PDB][-c, -b, -a] // ChristoffelToGradMetric // ToCanonical
Out[]= PDB[-b][g[-a, -c]]
We see this will be zero if the basis is associated to the metric, or in other words, if the metric has constant components in the basis B. More explicitly:
In[]:= ContractBasis[% // ToBasis[B], OverDerivatives -> True]
Out[]= PDB[{-b, -B}][g[{-a, -B}, {-c, -B}]]
Those g[{-a, -B}, {-c, -B}] are the scalar components of the metric in the basis B. All covariant derivatives agree on scalar fields, so the PDB in front is just any derivative. Our RRC will be antisymmetric in indices 1 and 3 if these are constants. Of course, xCoba doesn't know yet that you have constants, so the symmetry is not explict:
In[]:= SymmetryGroupOfTensor[ChristoffelcdPDB]
Out[]= StrongGenSet[{}, GenSet[]]
If you know this will be the situation you will be working on, you can add explicity the symmetry as you did:
SymmetryGroupOfTensor[ChristoffelcdPDB] ^= StrongGenSet[{1, 3}, GenSet[-Cycles[{1, 3}]]]
Now:
In[]:= Christoffel[cd, PDB][-a, -b, -c] + Christoffel[cd, PDB][-c, -b, -a] // ToCanonical
Out[]= 0
Cheers,
Jose.