torque question

[Seth Landon Schoming]

Does anybody know what '40 oz/inch' really means when it comes to torque?

I have two servos and I am trying to use them to control the pan and tilt on my camera (which only weighs 18.5 ounces) but I am having a hard time believing that these little servos are strong enough to move my camera. I am sure leverage is an issue.. Any ideas?

[John Harrison]

I think it means it can lift 40 Oz 1 inch for its entire sweep. So the
more inches you want move in a sweep the less Ozes.

> my camera. I am sure leverage is an issue.. Any ideas? --
> You received this message because you are subscribed to the Google
> Groups "wsu-engr101" group.
> To post to this group, send email to wsu-e...@googlegroups.com.
> To unsubscribe from this group, send email to
> wsu-engr101...@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/wsu-engr101?hl=en.

[Tom Tasker]

I'm more used to seeing in/oz or ft/lb, so I'm assuming that's what it is.
Torque is how you measure rotary force. If you are tightening a nut, and you put 1 pound of force on a wrench that is 1 foot long, that is 1 foot/pound. 1 pound of force on a six inch bar would be 1/2 foot/pound. So 40 in/oz expressed in foot pounds would

(40 in/oz) x (16oz/1lb) = 640in/lb
(640 in/lb) x (1ft/12in) =  53ft/lb

That seems like a lot of force so I might be off somewhere but  I don't see it yet.

---

From: Seth Landon Schoming <slsch...@wichita.edu>
To: wsu-e...@googlegroups.com
Sent: Mon, November 29, 2010 10:41:01 PM
Subject: [wsu-engr101: 369] torque question

Does anybody know what '40 oz/inch' really means when it comes to torque?

I have two servos and I am trying to use them to control the pan and tilt on my camera (which only weighs 18.5 ounces) but I am having a hard time believing that these little servos are strong enough to move my camera. I am sure leverage is an issue.. Any ideas?

--

[JAIME NORTH]

What it actually means is that it is capable of applying 40 ounces of lift at a distance of 1 inch from the pivot point.

On Nov 29, 2010 10:41 PM, "Seth Landon Schoming" <slsch...@wichita.edu> wrote:

Does anybody know what '40 oz/inch' really means when it comes to torque?

I have two servos and I am trying to use them to control the pan and tilt on my camera (which only weighs 18.5 ounces) but I am having a hard time believing that these little servos are strong enough to move my camera. I am sure leverage is an issue.. Any ideas?

--