Sending mail through python script using IITB proxy

[Jay Parikh]

Hi All,

I am trying to send mail using python script and IITB network to outside(gmail). But it is not working out.

I have tried several code but didn't work.
 

One of my sample code :

import smtplib
 
to = 'a...@gmail.com'
user = 'username'
pwd = 'pwd'
smtpserver = smtplib.SMTP("smtp-auth.iitb.ac.in",25)
smtpserver.ehlo()
smtpserver.login(user, pwd)
header = 'To:' + to + '\n' + 'From: ' + user + '@iitb.ac.in\n' + 'Subject:testing \n'
msg = header + '\n this is a test message\n\n'
smtpserver.sendmail(user, to, msg)
smtpserver.close()

Could anyone please help me out solving the problem ?

--

Thanks and Regards,

Jay.

PowerAnser Lab,

IIT Bombay.

[Dilawar]

Following was working for me.
 

            # Now construct the mail msg
            HOST = 'smtp-auth.iitb.ac.in'
            message = MIMEMultipart()
            FROM = 'som...@eee.iitb.ac.in'
            COMMMASPACE = ', '
            TO = [email_id]
            CC = ['dila...@iitb.ac.in'']


            message["From"] = "dila...@iitb.ac.in"
            message["To"] = unicode(TO)
            message["Subject"] = "Attached files are very similar. Meet your instructor!"
            message["Date"] = formatdate(localtime=True)


            f = open('msg.txt', 'r')
            text = f.read()
            text = text + msg
            text = text +'\n--\n' \
                    +'\nThis email is system-generated. You need not reply.'


            message.attach(MIMEText(text))
            # attach a file
            part = MIMEBase('application', "octet-stream")
            part.set_payload( open(tarfile_name,"rb").read() )
            Encoders.encode_base64(part)
            part.add_header('Content-Disposition', 'attachment; filename="%s"'\
                    % os.path.basename(tarfile_name))
            message.attach(part)
         
            # get username and password. Or hardcode it.
            username = os.getenv('proxy_username')
            password = os.getenv('proxy_password')


            server = smtplib.SMTP(HOST, 25)
            server.starttls()
            server.set_debuglevel(2)
            server.login(username, password) # optional
            try:
                print 'Sending email.'
                TO = TO + CC
                failed = server.sendmail(FROM, TO, message.as_string())
                server.close()
            except Exception, e:
                errorMsg = "Unable to send email. Error: %s" % str(e)


On Wednesday, June 18, 2014 3:11:22 PM UTC+5:30, Jay Parikh wrote:

[Pritam Baral]

Jay, you need to use CRLF, '\r\n' as separators on your header string.

I'd recommend using a library to construct messages, but for academic purposes, knowing the down-and-dirty details is always good.

 

Regards,
Chhatoi Pritam Baral

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[Pritam Baral]

Errata: ... '\r\n' as separators on your header string

[Amol Mandhane]

Adding 3 lines (highlighted) to your code. This should work.

import smtplib
 
to = 'a...@gmail.com'
user = 'username'
pwd = 'pwd'
smtpserver = smtplib.SMTP("smtp-auth.iitb.ac.in",25)
smtpserver.ehlo()

smtpserver.starttls()
smtpserver.ehlo()
smtpserver.esmtp_features['auth']='LOGIN DIGEST-MD5 PLAIN'

smtpserver.login(user, pwd)
header = 'To:' + to + '\n' + 'From: ' + user + '@iitb.ac.in\n' + 'Subject:testing \n'
msg = header + '\n this is a test message\n\n'
smtpserver.sendmail(user, to, msg)
smtpserver.close()

AM

[Jay Parikh]

Thanks Amol and everyone for suggestions and answers...

@Amol : Those 3 lines made my life. ;)  It worked. Thanks a lot.

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