How to weigh results not taking into account document length?

[Richard Nichols III]

Hi, what's the simplest way to get some results weighted without dividing by a log of document length? Basically I just want results in order of how many times any word from my search string appears in the document.

I tried this:

   with self.ix.searcher(weighting=scoring.WeightScorer(maxweight=1)) as searcher: #wtf do i do for maxweight?

      #was: with self.ix.searcher() as searcher:

        query = Or([Term("searchablecontent", token.text) for token in stream])

        results = searcher.search(query)

and I got this error:

  File "c:\limnoria\plugins\AIBot\plugin.py", line 46, in invalidCommand

    results = searcher.search(query)

  File "c:\python37-32\lib\site-packages\whoosh\searching.py", line 786, in search

    self.search_with_collector(q, c)

  File "c:\python37-32\lib\site-packages\whoosh\searching.py", line 817, in search_with_collector

    collector.prepare(self, q, context)

  File "c:\python37-32\lib\site-packages\whoosh\collectors.py", line 335, in prepare

    if top_searcher.weighting.use_final:

AttributeError: 'WeightScorer' object has no attribute 'use_final'

Thanks

[Vito Piepoli]

Have you tried with "weighting=scoring.Frequency"?

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[inhahe]

That seems to have worked, Thx.