Vector Canoe Download !LINK!
Melony Kai
Did any one use "Vector CANoe" tool kit in Simulink. I need to do my next project with such a combination. I searched in both matlab and vector websites for the add on tool kit but couldn't find. Would any one help on this?
The two CAN nodes( two TMS570LS3) works fine together. The issue is that we have the real vehicle CAN network here, and the CANoe is used to trace all the CAN communication on this network. Also the CANoe could simulate this CAN network. We want to add the TMS570LS3 as a node to this network, but failed both ways. Couldn't make TMS570LS3 communicate with either CANoe or the vehicle CAN network. I have already contact FAE from vector to discuss how to find the actual problem. Since the two TMS570LS3 could communicate with each other, FAE from vector suggested that I attached the CANoe to the communication CAN bus of TMS570LS3s, and use scan function of CANoe ( scan from baud rate 0kbps-1000kbps) to see whether CANoe could determine a suitable baud rate, but failed. And at least FAE from vector said that the CANoe has a relatively high tolerance to allow slight differently set CAN nodes to communicate with it.
The extension automatically detects an installation of CANoe or CANoe4SW. If you have more than one edition installed or, for any other reason, have a custom setup, you can manually adjust the extension setting vcdl.canoeDirectories. Please note that versions older than 17 SP3 are not supported. For these, we recommend using the built-in Vector Tools Environment for editing vCDL files.
If momentum is to be conserved, the canoe must head on a course slightly to the West of North to cancel out the Eastward momentum of the thrown object. The vector sum of the 2 pieces must be equal to the original momentum.
The component #v_(f1W)# represents the Westward component of the canoe in the final case. I said above that this is needed to cancel the Eastward momentum of the 50 kg object. Therefore, this must be true
#300 kg*v_(f1W) + 50 kg*0.25 m/s*hati = 0#
Now we need #v_(f1N)#. Conservation of momentum says that we still need #1750 kg*m/s*hatj# of momentum heading North. Same value as the initial momentum. That 50 kg mass has no Northward velocity. The canoe's component of momentum heading North, #v_(f1N)#, needs to be #1750 kg*m/s*hatj#.
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