Civil twilight list for a year

[P C]

Hello,

I would like to be able to generate a CSV file with the 365 or 366 days of any year with the dusk civilians (6 °) of the sun:
I include "hard" the year, and so these 3 output values:

date;
$almanac(horizon=-6).sun(use_center=1).rise;
$almanac(horizon=-6).sun(use_center=1).set

I know you have to use a model of the genre "crepuscules.csv.tmpl" etc.

It is of course at the level of the code that I am blocked: I do not see how to browse the dates.

Well to you,
Pascal

[Tom Keffer]

Something like this (NOT TESTED) should give you a table of sunrise and sunset:

    <table>
    #for $day in $year.days
      <tr>
        <td>$day.dateTime.format("%Y-%m-%d")</td>
        <td>$almanac(almanac_time=$day.dateTime.raw, horizon=-6).sun(use_center=1).rise</td>
        <td>$almanac(almanac_time=$day.dateTime.raw, horizon=-6).sun(use_center=1).set</td>
      </tr>
    #end for
    </table>

-tk

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[Blaise]

Ah Yesss, perfect !

#for $day in $year.days
$day.dateTime.format("%d/%m/%Y");$almanac(almanac_time=$day.dateTime.raw, horizon=-6).sun(use_center=1).rise;$almanac(almanac_time=$day.dateTime.raw, horizon=-6).sun(use_center=1).set
#end for

I'm starting to apprehend language (I was gone in a loop for Each)

However, the result takes into account the time zone but also summer / winter hours. Is it possible to have that in UTC 0?
And how to choose another year?

Thank you again, it's great for my automatons!

Le 03-04-21 à 15:14, Tom Keffer a écrit :

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[Tom Keffer]

There is no programmatic way to get the results in UTC, although I suppose you could subtract your UTC offset from the results.

For prior years, you can use the argument "years_ago". For example, for last year:

#for $day in $year(years_ago=1).days
$day.dateTime.format("%d/%m/%Y");$almanac(almanac_time=$day.dateTime.raw, horizon=-6).sun(use_center=1).rise;$almanac(almanac_time=$day.dateTime.raw, horizon=-6).sun(use_center=1).set
#end for

You really should look at the Customizing Guide. It's all in there.

-tk

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