Re: [webdriver] How to get only visible webelement from xpath?

[Simon Stewart]

Get all the elements using path and then iterate over them, filtering entries by a call to "isDisplayed".

Simon (from a phone)

On Jun 13, 2012 8:47 AM, "mohit khatri" <mohit.k...@gmail.com> wrote:

Hi,

I would like to fetch only those web element which are visible on page using xpath. But in the page source there is no "style" tag present. So how would i get those elements?

I'm using driver.findelement(By.xpath("")). I can get visible elements by driver.findelement(By.xpath("")).isDisplayed() but I don't want to use isDisplayed() method.

I just want to pass xpath of those elements which are visible on page. Below is sample html code of my webpage.

<div class="sdf">
<a rel="nofollow" id="Link_5" href="/abc-html" title="xyz" class="PQR">Button Name</a>
</div>

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[mohit khatri]

Is there any other way without using isDisplayed?

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[Mike Riley]

I don't think so, but why would you not want to use that method?

Once you have a list of all the elements, you build up a second smaller list of those that are displayed.  Where is the problem with that?

Mike

[suneel kumar]

isDisplayed() is consuming lot of time. If there is a way to fetch while finding itself, that would be much more faster.

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[AVINASH NIMBHORE]

In that case you can use WebDriverWait to wait for particular element to become visible[By applying ExpectedCondition class].
Here you can set timeout which you feel element may take for loading on page.
 

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[Nikhil Bhoski]

not sure exactly what you are looking at , but did you try using Rendered WebElement instead ..

Regards

NIkhil