Distinct by field don't work for firebird

[Константин Комков]

Hello!

db().select(db.tt_on_day.TIMETABLE_ID,distinct=db.tt_on_day.TIMETABLE_ID)

>>>SELECT DISTINCT ON (tt_on_day.TIMETABLE_ID) tt_on_day.TIMETABLE_ID FROM tt_on_day

with True - work

db().select(db.tt_on_day.TIMETABLE_ID,distinct=True)

>>>SELECT DISTINCT tt_on_day.TIMETABLE_ID FROM tt_on_day

And I don't understand one more thing. If I do query like that:

rows = db((db.t_fac.FULL_NAME != 'НЕИДЕНТИФИЦИРОВАННОЕ') &
              (db.a_groups.FO == 1) &
              (db.a_groups.INACTIVE == 0)).select(db.t_fac.id,db.t_fac.FULL_NAME,distinct=True,
                                                  join=[db.a_groups.on(db.tt_main.GROUP_ID == db.a_groups.id),
                                                        db.t_fac.on(db.a_groups.FAC == db.t_fac.id)])

Then I want to get id and FULL_NAME in circle:

faculties = {}

for row in rows:
        faculties[row.t_fac.id] = row.t_fac.FULL_NAME

but I have error, becouse row is dict now and I should write:

for row in rows:
        faculties[row['id']] = row['FULL_NAME']

Why row type is dict? For example,

<Row {'id': 1, 'a_groups': <Set (a_groups.FAC = 1)>, 'FULL_NAME': 'Агрономии и биотехнологии'}>.