how to get the message-id of a send mail

[selecta]

I was wondering if there is a proper way to get the message-id of a
send mail.
mail.send just returns true or false
So far I tried to send the mail also to my own account and guess from
comparing header and body that this is the mail that I send out. This
however gives me quite some headaches with all the different character
encodings ...

Is there a better way to get the message-id of a send mail?

[mdipierro]

What is the "message-id"?

[Bruno Rocha]

I guess you have to create table to store your sent messages, and a method which sends and store the send message.

db.define_table('sentmail',Field('to'),Field('from'),Field('body'))

def mail_sender(to,body):

    try:

        #send the mail

        .....

        .....

        return dict(status='sent',mail_id=db.sentmail.insert(to='',from='',body=''))

    except Exception, e:

        #report the failure

        #stores the message for send later

        return dict(status='fail',fail_id=db.unsentmails.insert())

2010/11/22 selecta <gr...@delarue-berlin.de>

--

Bruno Rocha

http://about.me/rochacbruno/bio

[selecta]

If you look into the header of an email message, you will find a key
called message-id, the value looks something like
<4CEA5D16...@biologie.hu-berlin.de> this message id is for
example used when you reply to a mail
then the header contains something like In-Reply-To:
<4CEA5D16...@biologie.hu-berlin.de>

I am currently working on a mailing-list plugin and for that I need
the message ids of the outgoing mails to see if incoming mails are
answers to resend incoming mails. This way I can build up a nice
treaded/tree view for all email communication.

Btw wouldn't it be nice to have a completely web2py based platform for
all web2py communication ;-)

[Bruno Rocha]

Is there a result dictionary in Mail class, method send.

http://code.google.com/p/web2py/source/browse/gluon/tools.py#549

But I dont know it this got message_id from the SMTP server.

2010/11/22 selecta <gr...@delarue-berlin.de>

[mdipierro]

Perhaps this:

result = server.sendmail(self.settings.sender, to,
payload.as_string())
server.quit()
except Exception, e:
logger.warn('Mail.send failure:%s' % e)
self.result = result
self.error = e
return False
self.result = result
self.error = None
return True

should be

result = server.sendmail(self.settings.sender, to,
payload.as_string())
server.quit()
except Exception, e:
logger.warn('Mail.send failure:%s' % e)
self.result = result
self.error = e
return False
self.result = result
self.error = None
return result

Any objection to change it?

On Nov 22, 8:12 am, Bruno Rocha <rochacbr...@gmail.com> wrote:
> Is there a result dictionary in Mail class, method send.
>
> http://code.google.com/p/web2py/source/browse/gluon/tools.py#549
>
> But I dont know it this got message_id from the SMTP server.
>
> 2010/11/22 selecta <gr...@delarue-berlin.de>
>
>
>
> > If you look into the header of an email message, you will find a key
> > called message-id, the value looks something like

> > <4CEA5D16.6010...@biologie.hu-berlin.de> this message id is for

> > example used when you reply to a mail
> > then the header contains something like In-Reply-To:

> > <4CEA5D16.6010...@biologie.hu-berlin.de>

[Bruno Rocha]

Returning "result" will not break the compatibility?

if someone has made a system which test  "if mail.send(...): ...." or "if mail.send(...) == True"   ?

2010/11/22 mdipierro <mdip...@cs.depaul.edu>

[Bruno Rocha]

Using this:

import smtplib

02	fromaddr = 'seue...@gmail.com'

03	toaddrs = 'destin...@gmail.com'

04	msg = 'Mensagem enviada pelo Python utilizando Gmail'

05

06	#provide gmail user name and password

07	username = 'seu email'

08	password = 'sua senha'

09

10	# functions to send an email

11	server = smtplib.SMTP('smtp.gmail.com:587')

12	server.ehlo()

13	server.starttls()

14	server.ehlo()

15	server.login(username,password)

16	server.sendmail(fromaddr, toaddrs, msg)

17	server.quit()

I got an empty result on shell

>>> result = server.sendmail(fromaddr,toaddr,msg)

>>> result

{}

>>> 

2010/11/22 Bruno Rocha <rocha...@gmail.com>

[Bruno Rocha]

Mey be having

mail.settings.returning_method = 'boolean' | 'dict'

??

2010/11/22 mdipierro <mdip...@cs.depaul.edu>

[mdipierro]

Returning a dict evaluates as True therefore I would not consider it a
breaking of backward compatibility. Unless objections I would not make
this more complex that needs to be. Moreover I am not sure what GAE
returns for sendmail.

Massimo

On Nov 22, 8:41 am, Bruno Rocha <rochacbr...@gmail.com> wrote:
> Mey be having
>
> mail.settings.returning_method = 'boolean' | 'dict'
>
> ??
>

> 2010/11/22 mdipierro <mdipie...@cs.depaul.edu>

[Bruno Rocha]

smtplib will return something just in case the server refuses a recipient, I guess you have to define the message-ID and send this in the mail header.

In fact, smtplib doesn't include any headers automatically, but just sends the text that you give it as a raw message

message = 'From: m...@example.com\nMessage-ID:<base64>\nSubject: [PGS]: Results\n\nBlaBlaBla'

I tested here, even GAE or smtplib returns a dict with invalid recipients when server refuse, when succed the dict returned is empty.

I found some more info here: http://bimbo.fjfi.cvut.cz/ppolicy/browser/trunk/ppolicy/tools/smtplib.py#L605

Guess you can generate an Message-ID with random or uiid

2010/11/22 mdipierro <mdip...@cs.depaul.edu>

[Bruno Rocha]

You can utilize the email.message.Message class, and use it to generate mime headers, includingfrom:, to: and subject. Send the as_string() result via SMTP.

>>> from email import message

>>> m1=message.Message()

>>> m1.add_header('from','m...@no.where')

>>> m1.add_header('to','mys...@some.where')

>>> m1.add_header('subject','test')

>>>m1.add_header('Message-ID',<base64ID>)

>>> m1.set_payload('test\n')

>>> m1.as_string()

'from: m...@no.where\nto: mys...@some.where\nsubject: test\n\ntest\nMessage-ID:<base64ID>'

>>>

2010/11/22 Bruno Rocha <rocha...@gmail.com>