@request.restful()
def icd10():
    import libxml2
    icd10_xml = libxml2.parseDoc(open('/home/www-data/web2py/applications'+URL('static','icd10/icd10cm/Tabular.xml'),'r').read())
    response.view = 'generic.xml'
    def GET(**vars):
        search_str = request.vars.search
        xpath_req = '//chapter/section/diag/desc[contains(text(),"'+search_str+'")]'
        diags = icd10_xml.xpathEval(xpath_req)
        concat = '<?xml version="1.0" encoding="utf-8"?><main>'
        for diag in diags:
            diag_str = str(XML(diag))
            concat = concat + diag_str
        concat = concat + '</main>'
        return concat
    return locals()Anthony
https://localhost/testapp/api/icd10.xml?search=string
Thanks for your input.
I removed the response.view and added the xml extension in the request:
and it worked. Is there any way to get an xml view without adding the xml extension?