MGT-613 GDB

[Arfan Ahmad]

REQUEST FOR IDEA SOLUTION OF MGT-613 GDB PLZ.

[mc090405332 Sumaira Rani]

attched

 

Solution:

Part 1)

QBEP = FC/ (R-VC)

QBEP = 80000/ (4000-400) = 22.22

22 cameras

Part 2)

Profit/loss = Q * (R-VC) - FC

Profit/loss = 100*(4000-400)-80000 = 280000

Part 3)

Q = (FC+P)/(R-VC)

Q = (80000+50000)/ (4000-400) = 36.11 = 36

36 cameras

On Fri, Jun 10, 2011 at 8:14 PM, Arfan Ahmad <majar...@gmail.com> wrote:

REQUEST FOR IDEA SOLUTION OF MGT-613 GDB PLZ.

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[mc090406030 Zafar Iqbal]

Dear given idea is correct. donot hesitate. send it after editing

[chand imran]

Solution:
1. How many cameras would be sold in order to break even?
Solution:
QBEP= FC/ ( R-VC)
=Rs. 80,000/ 4000-400= 80,000/3600
= 22.22 cameras = 22 Cameras
2. What would be the profit/loss if the 100 cameras are made and sold in 1 month?
Solution:
For Q =100 cameras, the Profit or Loss would be
P= Q(R-VC)-FC=100(4000-400)-80,000=100X 3600-80,000=360,000-80,000=280,000
3. How many cameras must be sold to realize a profit of Rs. 50,000?
Solution:
For P =50,000
Q = (FC+P)/ ( R-VC)=(80,000+50,000)/(4000-400)
=130,000/3600=36.11 = 36 Cameras

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