Unions,Intersections, and Difference...not in sequence

[Robert Cressman]

I entered the following code...

S1 = set([3, 5, 6, 10, 11, 100])
S2 = set([1, 3, 5, 6, 11, 15])
print(S1 | S2)
print(S1 & S2)
print(S1 - S2)

However, when it prints out, the resulting numbers are not sequential, which I believe they should be. Anyone have an idea what the problem is?

[Charles E Campbell]

Well, I changed that first line to "let S1=..." but I get

E117: Unknown function: set
E15: Invalid expression: set([3, 5, 6, 10, 11, 100])

I'm using vim, huge, 7.4.430 .

Regards,
Chip Campbell

[Bob]

My coding works without error, it just does not return the numbers in upward incrementation - just randomly.

Sent from my Verizon Wireless 4G LTE smartphone

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[LCD 47]

Wrong forum. This list is about Vim, not Python.

/lcd

[Tim Chase]

1) I'm pretty sure this isn't vim-script, as there's no set()
constructor that I know of

2) this looks an awful lot like Python, and sets in Python are
inherently unordered. If this is Python, you'd want to wrap the
contents of the print()s in sorted(). E.g., print(sorted(S1 - S2))

-tim

[Bob]

This code runs correctly in python. When I wrote it in vim is when problem occurs.

Sent from my Verizon Wireless 4G LTE smartphone

-------- Original message --------
From: LCD 47 <lcd...@gmail.com>
Date:09/06/2014 12:25 AM (GMT-07:00)
To: vim...@googlegroups.com
Cc:
Subject: Re: Unions,Intersections, and Difference...not in sequence

On 5 September 2014, Robert Cressman <bohi...@q.com> wrote:
> I entered the following code...
>
> S1 = set([3, 5, 6, 10, 11, 100])
> S2 = set([1, 3, 5, 6, 11, 15])
> print(S1 | S2)
> print(S1 & S2)
> print(S1 - S2)
>
> However, when it prints out, the resulting numbers are not sequential,
> which I believe they should be. Anyone have an idea what the problem
> is?

    Wrong forum.  This list is about Vim, not Python.

    /lcd

[Robert A. Cressman]

That did it! Thanks!
Bob

[Robert Cressman]

On Saturday, September 6, 2014 12:26:07 AM UTC-7, LCD 47 wrote:

> On 5 September 2014, Robert Cressman wrote:
>
> > I entered the following code...
>
> >
>
> > S1 = set([3, 5, 6, 10, 11, 100])
>
> > S2 = set([1, 3, 5, 6, 11, 15])
>
> > print(S1 | S2)
>
> > print(S1 & S2)
>
> > print(S1 - S2)
>
> >
>
> > However, when it prints out, the resulting numbers are not sequential,
>
> > which I believe they should be. Anyone have an idea what the problem
>
> > is?
>
>
>
> Wrong forum. This list is about Vim, not Python.
>
>
>
> /lcd

Just an FYI, I coded it in Python and it worked correctly. When I did it in vim, I got the errors.

[Boyko Bantchev]

> Just an FYI, I coded it in Python and it worked correctly. When I did it in vim, I got the errors.

As you have been pointed out already, sets in Python are unordered
collections. So, what you call 'correctly' is what you expect to be
the norm, but in fact it isn't.
And what you perceive as an 'error' is not one, according to Python's
definition, and is certainly not anything Vim has to do with.