What makes the difference ? | if and dict
Marc Weber
if (1 >= 1) | let d = 1 | else | let d = {'evalLazyClosedArgs': 1} | endif
You can execute the first line in cmd line.
The second fails. Why ?
Marc Weber
John Beckett
> if (1 >= 1) | let d = 1 | else | let d = "soo" | endif
> if (1 >= 1) | let d = 1 | else | let d = {'evalLazyClosedArgs': 1} | endif
The problem is simply that after you have execute the first line, the global
variable d contains a number (1). You're not able to change the type of a variable
from number to dictionary.
If you ':unlet d' before the second line, it works (:help E706).
John
John Beckett
> The problem is simply that after you have execute the first
> line, the global variable d contains a number (1). You're not
> able to change the type of a variable from number to dictionary.
On actually reading this, I see it quite misses the point.
Strangely, the first time I executed line 1 followed by line 2, I got your error. On
retrying, I do not. I have to go elsewhere ... may think later.
John
Matt Wozniski
Both seem to work for me... larger test case?
~Matt
Marc Weber
No. I must have had d defined as int or such then. I've had a problem
with this using exec and d should have been a local not yet defined var
there. I have to go to bed now. I just didn't see any error message.
Thanks
Marc Weber
John Beckett
> No. I must have had d defined as int or such then.
I've worked out where I went wrong. I was confused by the the 'evalLazyClosedArgs'
text (and wondered if the actual text was somehow relevant). I did a ":let d =
{'x':1}" before trying your command (putting a dictionary into d). But your command
tries to put the number 1 into d, which triggered the error.
John
Tony Mechelynck
Works for me. What error do you get?
Best regards,
Tony.
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