ANSWER:
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Let x1 be the numerical(approximate) soln to the linear system
Ax=b.
Residual r1 = b-Ax1
Solving the linear system Az1=r1, the "improved" soln to the
system Ax=b is x2 = x1+z1.
x2 is the better soln than of x1 because,
Residual r2 = b - Ax2
= b - A(x1+z1)
= b - Ax1 - Az1
= b - (b-r1) - r1
= 0.
- C.Thamayanthi
tche...@engmail.uwaterloo.ca