Very cool tool, congratulations!
For the last two years, I've been explaining posits a little differently than in the early papers and presentations. A regime that is all 0 bits represents –∞ (since it is an infinitely long string of 0 bits, since all bits after the LSB have value 0), and then the formula still works because you take 2 to the power of –∞, which is 0.
It also works, almost, for NaR, because a 1 bit followed by all 0 bits will be –(2^∞) = –∞ if you apply the formula, and that's certainly Not-a-Real. We just have to explain the convention that it is also the dumping ground for all other things that are Not-a-Real, like complex numbers, +∞, the entire real number line, the string "zebra", and so on. I think it would be a small edit to show the regime value as –∞ when it is all 0 bits, and still apply the formula. Remember that in comparison operations, NaR tests as less than any other posit, which is what –∞ does.
This explanation also helps explain why a regime consisting of all 1 bits does have a termination bit. It's the implied 0 bit right after the LSB.
I've been using the term "ghost bits" for the infinite string of 0 bits that follows the LSB of a posit.
Best,