> summary(umf)
unmarkedFrame Object
47 sites
Maximum number of observations per site: 45
Mean number of observations per site: 27.06
Sites with at least one detection: 9
Tabulation of y observations:
0 1 <NA>
1232 40 843
# global model
> print(obs.boot, digits.vals = 2, digits.chisq = 2)
MacKenzie and Bailey goodness-of-fit for single-season occupancy model
Pearson chi-square table:
Cohort Observed Expected Chi-square
010100110100011100100000000000000000000101000 0 1 0.00 641793093.97
000000000000000000000000000000000000000...... 1 1 1.00 0.00
000000000000000000000000000000000000......... 2 1 1.00 0.00
000010000000000000000101100000000000......... 2 1 0.00 32740.68
00000000000000000000000000000000000.......... 3 1 1.00 0.00
00000000010101000010001100000000000.......... 3 1 0.00 46120.00
0000000000000000000000000000000000........... 4 2 2.00 0.00
011111101011000001000000000000000............ 5 1 0.00 18542915.68
0000000000000000000000000000000.............. 6 1 1.00 0.00
000000000000000000000000000000............... 7 5 5.00 0.00
00000000000000000000000000000................ 8 3 3.00 0.00
0000000000000000000000000000................. 9 3 3.00 0.00
000000000000000000000000000.................. 10 1 1.00 0.00
00000000000000000000000000................... 11 2 2.00 0.00
0000000000000000000000000.................... 12 3 3.00 0.00
000000000000000000000000..................... 13 3 3.47 0.06
000000000001000000000000..................... 13 1 0.06 14.81
000000000100100000000000..................... 13 1 0.00 256.63
000001000000000010000000..................... 13 1 0.00 612.58
001000000000000010000000..................... 13 1 0.00 355.47
00000000000000000000000...................... 14 3 2.75 0.02
0000000000000000000000....................... 15 2 1.59 0.10
000000000000000000000........................ 16 3 3.00 0.00
00000000000000000000......................... 17 3 3.00 0.00
100100000000000000........................... 18 1 0.00 2273.61
00000000000000000............................ 19 1 1.00 0.00
Chi-square statistic = 660418393
Number of bootstrap samples = 1000
P-value = 0.652
Quantiles of bootstrapped statistics:
0% 25% 50% 75% 100%
9.1e+05 3.3e+08 2.1e+09 1.9e+10 3.3e+13
Estimate of c-hat = 0
Any thoughts would be greatly appreciated.
Thanks,
- Joe