The first thing I would say is that lighter than air ballooning has been around for well over 200 years and if there was some simple scheme like this for increasing maximum altitude then it would have been discovered and be well known by now. But all questions are valid.
The thing that mostly sets the maximum altitude a balloon can get
is the size it can reach without bursting. This will be mainly
determined by the differential (inside to outside) pressure
difference. The altitude this occurs is set by the amount of gas
fill at launch (and that dictated by the balloon weight + payload
weigh and the desired ascent speed).
There are other effects going on such as the temperature
affecting the balloons properties, gravity decreasing slightly
with altitude but these less important. Issues such as entering
float due to slow ascent rate have also been ignored.
All that would happen in your 2 balloon design is that as the 1st
balloon would need more gas to lift the added weight of the 2nd
balloon - at some pint before burst the 1st balloon it would start
to transfer gas to the 2nd balloon until such time they were equal
pressure. At which point they would continue to ascend until one
of the burst - which will be the same as if that balloon alone had
been released with the amount of gas it contained at burst
Steve
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The highest balloon got to 53km - there is to reason better
materials should not be able to get a balloon higher - but I doubt
that even the lowest of Low Earth Orbit altitudes 250km? can ever
be reached.
The atmospheric scale height of the earth is about 8.5Km - that
means (very roughly) for every additional 8.5Km in height, the air
density decreases by a factor of e (2.71828183...) - meaning to
get 8.5km higher the balloon would have to encompass 2.71828183x
the volume while retaining the same weight. The volume of a
balloon is proportional to the radius cubed while the surface area
proportional to the radius squared (the weight of the balloon
being related to the surface area and skin thickness) - so my
rough calculation suggests that for every 8.5Km the material
strength would have to increase by a factor of about 2. I.e. it
would have to get thinner by a factor of 2 or lighter by a factor
of 2 - while retaining the same tensile strength).
There are 23 x 8.5km between 53km and 250km - so good luck finding a material 2^23 (8,000,000x) stronger than the 53km balloon.
I admit this is all rough and ready calculation - and the upper atmosphere may not follow the scale height rule exactly - but it won't be hugely out.
Steve
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