The answer to the question is to carry out some measurements and do the
sum so that you know for sure...
First job, is you need to know your earth loop impedance. There are
three ways you can tackle this. The best is to measure it with an
appropriate meter. The next would be to ask the supplier, and lastly
you could assume a nominal "worst case" value for the type of earthing
(0.8 ohms for TN-S supplies, and 0.35 for TN-C-S (PME)).
Let's say you have a BS1361 100A incomer, and a TN-C-S supply. You don't
know the ELI (aka Ze), so assume the 00.35 ohms.
That means your prospective fault current is 230 / 0.35 = 657 A
So look at the characteristics of the fuse:
http://wiki.diyfaq.org.uk/images/0/06/Curve-BS1361.png
From the table you can see that with only 657A of fault current it will
take getting on for 5 secs to open the fuse.
Now all we need to know is what CSA of copper is required to withstand
that fault current for 5 secs. This we can calculate with the Adiabatic
check:
s = sqrt( 657^2 x 5 ) / 115
(where 115 is the k factor for PVC insulated cable)
s = 12.7mm
So in that case, 10mm is not enough.
However, if you now go and measure your ELI and find it is actually say
0.1 ohms, you get a different result.
The PFC goes up to 230 / 0.1 = 2300A
That opens the fuse in 0.1 secs, and the earth conductor size required
becomes:
s = (2300^2 x 0.1 ) / 115 = 6.32mm
Hence in that case a 10mm earth is fine.