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小弟碰到了一些麻煩
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Vision
May 24, 2003, 1:35:03 PM5/24/03
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小弟碰到了一些麻煩:
char x[] = {0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08};
int *v1 = &x[4],**v2 = &v1,a = **v2;
……
請問在linux,x86平台下,a = ? (能加上說明更好)
char x[] = {0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08};
int *v1 = &x[4],**v2 = &v1,a = **v2;
……
請問在linux,x86平台下,a = ? (能加上說明更好)
E-mail:lm...@seed.net.tw
一定當面感謝
coco
May 24, 2003, 11:19:53 PM5/24/03
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Vision <lm...@seed.net.tw> wrote in message news:<3ECFAD4...@seed.net.tw>...
> 小弟碰到了一些麻煩:
> char x[] = {0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08};
> int *v1 = &x[4],**v2 = &v1,a = **v2;
> ……
> 請問在linux,x86平台下,a = ? (能加上說明更好)
>
編譯器應不會過，因為
int *v1 = &x[4]....
&x[4] 不是 int * 型態！
> 小弟碰到了一些麻煩:
> char x[] = {0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08};
> int *v1 = &x[4],**v2 = &v1,a = **v2;
> ……
> 請問在linux,x86平台下,a = ? (能加上說明更好)
>
int *v1 = &x[4]....
&x[4] 不是 int * 型態！
程式改成型態一致：
int x[] = {0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08};
int *v1 = &x[4],**v2 = &v1,a = **v2;
結果 a=0x05，因為 **v2==x[4]
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