@ Rohan's doubt (lack of infomation in the previous post)

[Sarita Math]

Qu. To determine the limit of (x^3 + y^3)/(x + y^2) at x,y->0,0

Ans. Previously I've said you to put x= r cos(t), y= r sin(t). and make r tend to 0. In this case, you have to notice whether the denominator exists for every values of t or not which I forget to mention and the denominator comes cos(t)+r sin(t), if you take t=pi /2 and make r tends to 0, it will be 0. So, the polar transformation will not work here for sure. Sorry, I didn't notice that.

Well, Rohan suggested a path x = -y^2 (making denominator equals to 0). Along this path, the limit is undefined. In other words, limit does not exist.

If you have any more suggestion, write below this post.

[Bodepu Lavanya]

sorry mam i got it clarified


On 9/23/12, Sarita Math <sarita...@gmail.com> wrote:
> *Qu. To determine the limit of (x^3 + y^3)/(x + y^2) at x,y->0,0
> *
> *
> *
> *Ans*. Previously I've said you to put x= r cos(t), y= r sin(t). and make r

>
> tend to 0. In this case, you have to notice whether the denominator exists
> for every values of t or not which I forget to mention and the denominator
> comes cos(t)+r sin(t), if you take t=pi /2 and make r tends to 0, it will
> be 0. So, the polar transformation will not work here for sure. Sorry, I
> didn't notice that.
> Well, Rohan suggested a path x = -y^2 (making denominator equals to 0).
> Along this path, the limit is undefined. In other words, limit does not
> exist.
>
> If you have any more suggestion, write below this post.
>

> --
>
>
>