Hello! I just have a quick question about the redshifts zA and zB. In equation 6 of the method paper, the limits of integration are from zA to zB. The paper defines the observer to sit at point B and the lightray to go from point A to point B. This means that the source of the light (the quasar, for instance) sits at point A and Trident is following the path of the light as it moves from the quasar at point A to the observer at point B. Also, the paper defines the redshift of the simulation output to be that of zA.
In Hogg 1999 (the paper cited for equation 6), his limits of integration are from the redshift of the observer to the redshift of the source, which is the opposite of what equation 6 has. However, Hogg also implies that the redshift of the observer is less than the redshift of the source (that is, zB < zA). If this is the case, then the dz intervals given by equation 8 will be negative, since, as I understand it, dl is just the magnitude of the line segment, and therefore positive. This confuses me since this implies, from equation 9, that zi < zB. Doesn't that take you outside the bounds of the line of sight? That is, shouldn't zi > zB in order to "march towards" zA at the other end of the line of sight? If, however, zB > zA you still have the same problem, since dz will be positive and adding a bunch of positive numbers to zB will only make it larger, still taking you away from zA. Unless there's an implied negative sign in l in equation 6 due to the limits being flipped?
So, my first question is whether or not zB < zA or not and which direction is defined to be positive?
My second question also concerns that sum in equation 9. The sum is from j = 1 to j = n, and the paper says that the lightray is broken into n segments, so that implies that the sum is over every segment? Wouldn't it need to only go from zB to the i'th segment?
I don't think the paper is wrong, I'm just clearly misunderstanding something about how the sight line is being constructed, so any help understanding it would be greatly appreciated. Thank you very much!
Sincerely,
-Jared