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The current answer is no, owl:disjointUnionOf is not supported. I haven't seen enough use cases of it. The more traditional owl:disjointWith is supported by the converter.
Holger
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Ok, thx Holger.
Any tips of best manual translation would be great.
The owl would be:
<owl:Class rdf:ID="Document">
<rdfs:label xml:lang="en-GB">Document</rdfs:label>
<rdfs:comment xml:lang="en-GB">abstract class for references to a document; an individual shall at least be member of ct:ExternalDocument or ct:InternalDocument; and optionally, individuals can be a member of other subtypes of ct:Document such as ct:SecuredDocument and/or ct:EncryptedDocument</rdfs:comment>
<owl:disjointUnionOf rdf:parseType="Collection">
<owl:Class rdf:ID="ExternalDocument"/>
<owl:Class rdf:ID="InternalDocument"/>
</owl:disjointUnionOf>
</owl:Class>
Guess some sh:node sh:or sh:node shape patern but how to indicate completeness?
Thx !
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On 26 Jun 2019, at 08:40, 'Bohms, H.M. (Michel)' via TopBraid Suite Users <topbrai...@googlegroups.com> wrote:Ok, thx Holger.Any tips of best manual translation would be great.The owl would be:<owl:Class rdf:ID="Document"><rdfs:label xml:lang="en-GB">Document</rdfs:label><rdfs:comment xml:lang="en-GB">abstract class for references to a document; an individual shall at least be member of ct:ExternalDocument or ct:InternalDocument; and optionally, individuals can be a member of other subtypes of ct:Document such as ct:SecuredDocument and/or ct:EncryptedDocument</rdfs:comment><owl:disjointUnionOf rdf:parseType="Collection"><owl:Class rdf:ID="ExternalDocument"/><owl:Class rdf:ID="InternalDocument"/></owl:disjointUnionOf></owl:Class>Guess some sh:node sh:or sh:node shape patern but how to indicate completeness?
Thx !
Dr. ir. H.M. (Michel) Böhms
Senior Data Scientist
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I interpret the disjointUnion as:
Say X = A B C
In that case sh:in seems only address the second bullit?
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On 27 Jun 2019, at 10:21, 'Bohms, H.M. (Michel)' via TopBraid Suite Users <topbrai...@googlegroups.com> wrote:I interpret the disjointUnion as:Say X = A B C
- A B and C are mutually disjunct
- X is in A or B or C
- There is no D
In that case sh:in seems only address the second bullit?
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I interpret the disjointUnion as:
Say X = A B C
- A B and C are mutually disjunct
- X is in A or B or C
- There is no D
In that case sh:in seems only address the second bullit?
Dr. ir. H.M. (Michel) Böhms
Senior Data Scientist
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