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Soruda olusturulan kod 54013
Xin bir rakam oldugunu göz önünde bulundurarak
7k+5=x+5 ,x=7k buradan 0ve 7 degerleri icin 5 kodunu olusturabiliriz
7k+4=x+5 x=7k-1 , 6 degeri olabilir
7k+0=x+5 x=7k-5 2 ve 9 degeri olabbilir
7k+1=x+5 x=7k-4 1 degeri olabilir
7k+3=x+5 7k-2=x 5 olabilir
Yani her bir basamaktaki kodu olusturmak için olabilecek kac deger varsa bunların carpımı bize bu kodun olusturulabilmesi
İcin kac farklı kod oldugu bulunur
2*1*2*1*1=4
Okan
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Mar 12, 2016, 11:16:12 AM3/12/16
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TEŞEKKÜRLER
12 Mart 2016 Cumartesi 11:58:43 UTC+2 tarihinde semanur s yazdı: