ti nspire settings ?

[Brit Hendricks]

Hey everyone,

I have a ti nspire cx cas.
When I enter
d/dt(e^(-it)) = -sin(t)+cos(t)i

I notice this is rectangular form but I would rather enter in this derivative
and get ie^it

Is there a setting I can alter to do this? I would like to keep answers out of the trig expressions.
Any help would be appreciated!

Britt

[Brit Hendricks]

Here is more information,

using my calculator:
integral of e^(it) dt = sin(t)-cos(t)i

by hand I get
integral of e^(it) dt = e^(it) / i = -i e^(it)

(i is the complex number)

[Brit Hendricks]

Does anyone know if there is a setting I can change to allow the answers to stay in complex exponential format instead of converting with Euler formula?

On Wednesday, June 25, 2014 10:04:53 AM UTC-4, Brit Hendricks wrote:

[Dennis Donovan]

Try on the Document Settings Page (Home -> 5: Settings -> 2: Document Settings) on the Real or Complex line - Select Polar instead of Rectangular.

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From: Brit Hendricks <hendri...@gmail.com>
To: tins...@googlegroups.com
Sent: Wednesday, June 25, 2014 11:45 AM
Subject: [tinspire] Re: ti nspire settings ?

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[Brit Hendricks]

This was my first thought. However I do not get the form I am after sadly. I will keep searching though.
please post again if you have any other ideas!

Thanks

[Brit Hendricks]

I found out that this doesn't work for the cas nspire.
Darn...

here is why,
https://groups.google.com/forum/#!topic/tinspire/Dbl-4LtokMg

[Dennis Donovan]

What version are you running?  It seems to work under 3.6, the screen shots attached shows the result on the first line is when the setting was rectangular and the 2nd line is when the setting was in polar.  Both expressions for d/dt(e^(-it)) are equivalent to -i*e^(-it), and both expressions for d/dt(e^(it)) are equivalent to i*e^(it).

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From: Brit Hendricks <hendri...@gmail.com>
To: tins...@googlegroups.com

Cc: ddh...@yahoo.com
Sent: Monday, June 30, 2014 10:48 PM
Subject: Re: [tinspire] Re: ti nspire settings ?

[Brit Hendricks]

hey ddhawk1,

I have 3.6
Answers you got are still in polar form. If there is a way to convert that to exponential form that would be of help.
https://groups.google.com/forum/#!topic/tinspire/Dbl-4LtokMg
The link talks exactly about what I am looking for. It turns out that there is not a way to manipulate the answers to look like complex exponentials.