a filter question: two fields has value then NO else YES

[Mohammad Rahmani]

Question: There is a tiddler say myTiddler, a button shall be visible if and only if both fields of fone and ftwo  have non empty values

I know this can be done using two $list widgets but I am looking for a simpler more semantic solution!

Pseudo code

<$vars disabled={{{ if [[myTiddler]get[fone]!is[blank]]  AND  [[myTiddler]get[fone]!is[blank]] then NO else YES }}} >

<$button disabled=<<disabled>> > Create </$button>

</$vars>

What do you think?

Best wishes

Mohammad

[Mohammad Rahmani]

One solution I came up with is as below.

Note here the two fields are name (fone) and colorsheme (ftwo)

\define tmpTid() myTiddler

<$vars   disabled={{{[<tmpTid>get[name]!is[blank]then[no]else[yes]] :intersection[<tmpTid>get[colorscheme]!is[blank]then[no]else[yes]] ~[[yes]]}}} >
<$button actions=<<newPalette>> disabled=<<disabled>>>Create</$button> 
</$vars>

This is an ugly solution! I am looking for a simpler, more semantic and easy to follow!

Note ii: the button is working if two fields are not empty at the same time!

Best wishes

Mohammad

[Eric Shulman]

On Saturday, March 20, 2021 at 9:45:23 AM UTC-7 Mohammad wrote:

<$vars   disabled={{{[<tmpTid>get[name]!is[blank]then[no]else[yes]] :intersection[<tmpTid>get[colorscheme]!is[blank]then[no]else[yes]] ~[[yes]]}}} >

This is an ugly solution! I am looking for a simpler, more semantic and easy to follow!

You can use the "has[...]" filter which, by default, looks for non-empty field values.

You can also combine both field tests into one filter run.

Thus:

<$vars disabled={{{ [<tmpTid>has[name]has[colorscheme]then[no]else[yes]] }}}>

 enjoy,

-e

[Mohammad Rahmani]

Hi Eric,

Wonderful! Works like a charm!

 

 enjoy,

-e

Thank you

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