I'm reading the procedure for Lab 21-1, but am a little confused. I think the two questions below are related. Any help is greatly appreciated.
- What are the two layers?
- At the end of the synthesis I'm supposed to have brown solution, which contains impurities such as ethanol. I think I'm supposed to add water to the brown solution and expect to get two layers. What are the two layers? At first, I thought I would get aqueous layer (water) and organic layer (ethanol), but ethanol is miscible with water, so I don't think I'll get ethanol layer. But I think Methyl Salicylate dissolves in methanol, which dissolves in water, ....but that aqueous layer is thrown away???
- How is the methanol removed?
- At the end of "Isolate and purify the product" section, I'm supposed to wash the brown solution with water and then with sodium bicarbonate solution. How is methanol removed from the brown solution? Is it removed with the water wash? But I thought methanol is what the Methyl Salicylate dissolves in, so I would think you want to keep the methanol. But then I don't see any step to remove methanol. It seems to me, at the end of the sodium bicarbonate wash, you retain the layer that contain the Methyl Salicylate, or is that layer IS the Methyl Salicylate?
Thank you very much for your help.
Kenji