geometric algebra neglect denominator in inv() when Format(ipy=True)

[chaowen guo]

A test example:

import sympy.galgebra
sympy.galgebra.Format(ipy=True)
base=sympy.galgebra.MV.setup('e*1|2')
str(sympy.galgebra.MV.I.inv())

output: '-\\bm{e_{1}\\W e_{2}}'
and the output just print the numerator and neglect denominator

because the correct answer is:
str(sympy.galgebra.MV.Iinv)
output: '- \\frac{1}{\\lp e_{1}\\cdot e_{1}\\rp  \\lp e_{2}\\cdot e_{2}\\rp  - \\lp e_{1}\\cdot e_{2}\\rp ^{2}}\\bm{e_{1}\\W e_{2}}'
now it has numerator and denominator

Chaowen GUO

[Mike Boyle]

This bug apparently shows up with some help from the formatting method.  In particular, if you take out the 

sympy.galgebra.Format(ipy=True)

line, you get the correct answer.

The formatting code in galgebra is a bit of a mess, and in fact the whole project is moving out of sympy to its own project.  Anyway, I've opened up a bug report about this on github.  In the meantime, I suggest you just stick to ugly formatting.

[Alan Bromborsky]

Using galgebra at github.com/brombo/galgebra

and

from ga import Ga
base = Ga('e*1|2')
I = base.I()
Iinv = I.inv()
print 'I =',I
print '1/I =',Iinv
print 'I*(1/I) =',I*Iinv

I get

I = e_1^e_2/sqrt(Abs((e_1.e_1)*(e_2.e_2) - (e_1.e_2)**2))
1/I = -sqrt(Abs((e_1.e_1)*(e_2.e_2) - (e_1.e_2)**2))*e_1^e_2/((e_1.e_1)*(e_2.e_2) - (e_1.e_2)**2)
I*(1/I) = 1

Somethings have changed quite a bit.  Look at the documentation at github.com/brombo/galgebra

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