how to let ccode to print sympy.I as 1i, the c++ 14 style

[chaowen guo]

Hi:

The output of sympy.ccode(1+sympy.I) is '1+I'

However, in c++14 mode, like g++ -std=c++14 source.cpp, the g++ compiler does not think I is the imaginary unit.

But in the http://en.cppreference.com/w/cpp/numeric/complex, I know that after

using namespace std::complex_literals;
I can use 1i to represent the imaginary unit.

So how to tell ccode not to convert sympy.I into I but 1i?

I just know that there just exists ccode to convert sympy expression into c code. But I can not find any cppcode to convert sympy expression into c++ code.

[Jason Moore]

You can subclass the CCodePrinter and change the method for sympy.I to print as you like. Examples are here: http://docs.sympy.org/latest/modules/printing.html

Jason
moorepants.info
+01 530-601-9791

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[Aaron Meurer]

A cppcode would be useful to have for things like this (or just a flag
to ccode if the differences are minor).

Aaron Meurer

> https://groups.google.com/d/msgid/sympy/CAP7f1AiF55f8Q2hm%2BK27E39-HS%3DGL5VKxqNUcJrzEhKE_fbHbQ%40mail.gmail.com.