Help please

[muhammad ramadani fatsey]

Traceback (most recent call last): File "/tmp/sessions/c380e6d285d9328d/main.py", line 6, in <module> Eq((r1-r3)((1-cos(theta-phi)* ddotphi-sin(theta-phi)*dotphi**2)-2*(r1-r2)*ddottheta,g*sin(theta)))],[ddottheta,ddotphi])) TypeError: 'Add' object is not callable

what am I missing here?

from sympy import *

a,b,r1, r2, r3, m1,m2,theta,phi,dottheta, dotphi, ddottheta, ddotphi, g=symbols('a b r1 r2 r3 m1 m2 theta phi dottheta dotphi ddottheta ddotphi g')

print(solve([Eq((m1+m2)*(2*(r1-r3)*ddotphi+g*sin(phi))-m2*(r1-r2)*((1-cos(theta-phi))* ddottheta+sin(theta-phi)*dottheta*2),0),

Eq((r1-r3)((1-cos(theta-phi)* ddotphi-sin(theta-phi)*dotphi**2)-2*(r1-r2)*ddottheta,g*sin(theta)))],[ddottheta,ddotphi]))

[Matthew Brett]

The best technique is to strip down the problem to the smallest part
that produces the error.

In your case, you include this expression:

Eq((r1-r3)((1-cos(theta-phi)*
ddotphi-sin(theta-phi)*dotphi**2)-2*(r1-r2)*ddottheta,g*sin(theta)))

The (r1-r3) produces an Add object, and the parentheses that follow
try to call that Add object with the value inside the parentheses...

Maybe you meant to multiply like this?

Eq((r1-r3) * (1-cos(theta-phi)*
ddotphi-sin(theta-phi)*dotphi**2)-2*(r1-r2)*ddottheta,g*sin(theta))

[Oscar Gustafsson]

Should be a * after (r1-r3).

Eq((r1-r3)*((1-cos(theta-phi)* ddotphi-sin(theta-phi)*dotphi**2)-2*(r1-r2)*ddottheta,g*sin(theta)))],[ddottheta,ddotphi]))

BR Oscar

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