Sympy limit - result depends on the sign

[Paul Royik]

Hello.

I'm trying to calulate limit as x approaches infinity of e^((t-1)x)

Naturally, I got Notimplemented error Result depends on the sign of sign(t - 1).

My question how can I in general make assumption that this limit is finite?

I mean in general, because expression for limit can be arbitrary.

Thank you.

[Chris Smith]

Do you mean something like this?

>>> var('x')
x
>>> var('t',nonpositive=True)
t
>>> limit(E**((t-1)*x),x,oo)
0

[Paul Royik]

Yes.

Is there any way to tell, that t>1 ?

[Amit Saha]

On Fri, Apr 10, 2015 at 4:54 PM, Paul Royik <distan...@gmail.com> wrote:
> Yes.
> Is there any way to tell, that t>1 ?

I believe, no. I asked this sometime back. [1]

[1] https://groups.google.com/forum/?utm_medium=email&utm_source=footer#!msg/sympy/FC4cCBdKrs0/PJ9WgPzpIhUJ

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